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3 years ago

What is an equation of the line that passes through the points (5, 2) and (-5, -6)?

Mathematics

2 answers:

lawyer [7]3 years ago

8 0

Answer:

y=4/5x + 2

Step-by-step explanation:

y=mx+b

find slope which is 8/10=4/5

choose a y and plug into problem

Natasha2012 [34]3 years ago

8 0

Answer:

y = (4/5)x - 2

Step-by-step explanation:

First we must find the slope. This is calculated by dividing the difference of the y-coordinates by the difference of the x-coordinates.

Δ y-coordinates: 2 - (-6) = 2 + 6 = 8

Δ x-coordinates: 5 - (-5) = 5 + 5 = 10

slope = m = 8/10 = 4/5

Now, we can write the line in slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.

Choose (5, 2) (or you can use (-5, -6); it should get you the same answer) to plug into the equation to solve for b:

y = mx + b

2 = (4/5) * 5 + b

b = 2 - 4 = -2

Thus, our equation is y = (4/5)x - 2.

~ an aesthetics lover

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3 years ago

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SVETLANKA909090 [29]

Answer:

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2 years ago

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Yo please help

Alex Ar [27]

Answer:

Options 1, 3 and 4 are true

Step-by-step explanation:

The legs EF and DF of the right triangle DEF have lengths of 24 units and 7 units, respectively. By the Pythagorean theorem,

$DE^2=EF^2+DF^2\\ \\DE^2=24^2+7^2\\ \\DE^2=576+49\\ \\DE^2=625\\ \\DE=25\ units$

Find trigonometric functions:

$\sin \angle D=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{EF}{DE}=\dfrac{24}{25}$

$\cos \angle E=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}=\dfrac{EF}{DE}=\dfrac{24}{25}$

$\tan \angle D=\dfrac{\text{Opposite leg}}{\text{Adjacent leg}}=\dfrac{EF}{DF}=\dfrac{24}{7}$

$\sin \angle E=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{DF}{DE}=\dfrac{7}{25}$

Thus, options 1, 3 and 4 are true

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3 years ago

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2 years ago

What is an equation of the line that passes through the points (5, 2) and (-5, -6)?​

What is an equation of the line that passes through the points (5, 2) and (-5, -6)?