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Brrunno [24]
3 years ago
12

I need help ASAP with this

Mathematics
1 answer:
kari74 [83]3 years ago
6 0

Answer:

periodeee

Step-by-step explanation:

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Answer:

y , add 7, multiply by 3, then subtract 6.or Solve the system of equations and choose the correct answer from the list of options. x − y = 7 y = 3x + 12 2 over 19 comma 2 over 33 negative 2 over 19 comma negative 33 over 2 negative 19 over 2 comma negative 33 over 2 19 over 2 comma 33 over 2

Step-by-step explanation:

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3 years ago
Lines DE and AB intersect at point C.
lakkis [162]

Answer:

B

Step-by-step explanation:

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3 years ago
Estimate the size of a crowd walking in a charity fundraising march that occupies a rectangular space with dimensions of 10 feet
jolli1 [7]

Answer:

4000 is size of a crowd walking in a charity fundraising March.

Step-by-step explanation:

Given:

Dimensions of rectangular space 10 feet by 12000 feet

So we can say that,

Length = 1200 ft

Width = 10 ft

Now we will calculate the area of rectangular space which is given by

Hence Area will be = length\times width= 10\ ft \times 1200 \ ft= 12000 \ ft^2

Now we know that 40 people occupy a rectangle measuring 10 feet by 12 feet.

Length = 12 ft

Width = 10 ft

Area = length\times width= 10\ ft \times 12 \ ft= 120 \ ft^2

It says that 40 people are occupied in 120 ft^2

So how many people will be there in 12000 ft^2

By using unitary method we get,

Number of people = \frac{40\times 12000 \ ft^2}{120 \ ft^2} = 4000 \ peoples

Size of a crowd walking in a charity fundraising March is 4000.

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