2(y+1) = 3 LCD is 4
2*y + 2*1 = 3
2y + 2 = 3
2y = 3 - 2
2y = 1
y = 1 / 2
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2(y+1) = 3 LCD is 4
2*y + 2*1 = 3
2y + 2 = 3
2y = 3 - 2
2y = 1
y = 1 / 2
To calculate the relative vector of B we have to:
The coordenates of:
, with respect to B satisfy:
Equating coefficients of like powers of t produces the system of equation:
After solving this system, we have to:
And the result is:
Learn more: brainly.com/question/16850761