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Alborosie
2 years ago
13

ANSWER THISSSS AS GIVEN PLEASEEEEEEE

Mathematics
2 answers:
julsineya [31]2 years ago
8 0

Answer: x = 1

Step-by-step explanation:

Apply the exponent rule for multiplication, add the exponents

3^{2x+3+x-2}=81

3^{3x+1}=81

Convert 81 into exponential form with a base of 3

3*3*3*3=81

3^4=81

3^{3x+1}=3^4

Since the bases are the same, set the exponents equal

3x+1=4

3x=3

x=1

Savatey [412]2 years ago
4 0

Answer:

maybe 30?????

Step-by-step explanation:

sorry if it wrong I'm in the Same finals

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3 years ago
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

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Read 2 more answers
Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
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(a/b)/(c/d)=(ad)/(bc)
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(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
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so

4.
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\frac{(c^{-2})^{-2}}{2^{-2}}=

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4c^4



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\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

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Add 13 to both sides
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