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Elena-2011 [213]
3 years ago
14

Holsen wants to know the theoretical and experimental probability of rolling a number larger than a 3 on a 6-sided number cube n

umbered 1 to 6. He rolls the number cube 6 times and records the results in this table.
Mathematics
1 answer:
Novosadov [1.4K]3 years ago
8 0

Answer:

I need more info to help you answer the question

Step-by-step explanation:

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Write an equivalent expression for 4(2x+5
Verizon [17]
4(2x +5) = (8x + 20) 

8x =20 is an equivalent expression
 

8 0
3 years ago
Read 2 more answers
Factor completely: 10ax + 5bx - 8ay - 4by
kiruha [24]
The answer is (5x - 4y)(2a + b)

10ax + 5bx - 8ay - 4by = 10ax + 5bx - (8ay + 4by) =<span>
                                      = 5x * 2a + 5x * b - (2a * 4y + b * 4y) =
                                      = 5x(2a + b) - 4y(2a + b) = 
                                      = (5x - 4y)(2a + b)</span>
4 0
3 years ago
What is the ratio of 20cm to 1m​
Julli [10]

9514 1404 393

Answer:

  1 to 5

Step-by-step explanation:

20 cm to 1 m = 20 cm to 100 cm = 20 to 100 = 1 to 5

3 0
3 years ago
If the marginal propensity to consume is 0.8, (a) what is the value of the multiplier?
pentagon [3]
Given the marginal propensity to consume (MPC), the miltiplier is given by

Multiplier = 1 / (1 - MPC)

Given that the marginal propensity to consume is 0.8, the multiplier is given by

Multiplier = 1 / (1 - 0.8) = 1 / 0.2 = 5
7 0
3 years ago
What is the answer ?
notka56 [123]

Answer:

A) 2

Step-by-step explanation:

I<em>n a box-and-whisker plot, the left "whisker" is the bottom 25%, the line between the two "boxes" is to 50%, and the right "whisker" is the top 25%</em>.

In class 2, the 90 point mark is where the line between the boxes are, which means that 50% of the class earned 90% or less. That is 13/2 = <em>6.5 people</em> (this is impossible but it will work out)

In class 1, the 80 point mark is also where 50% is. So, half of the students, 17/2 = <em>8.5 people</em>, have 80 points or less.

<em>8.5 - 6.5 =</em> 2 people.

4 0
4 years ago
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