It would be 4 because the graph is showing the impact of heat on the enzyme not the pH. The pH in this instant is the constant and the graph does not indicate what a change in pH would do, only what a change in temperature would do.
Explanation:
A.
Yes
B.
2KHP + Mg(OH)2 = 2KOH + Mg(HP)2
KHP is an acidic salt which reacts with Mg(OH)2 which is a base via double displacement/decomposition reaction.
C.
• One approach is to prepare the solution volumetrically using KHP crystals.
• Preparing 1 liter of 0.1 M KHP you would add 0.1 moles of KHP
Molar mass of KHP(C8H5KO4)
= (12*8) + (5*1) + 39 + (16*4)
= 204 g/mol
Number of moles = mass/molar mass
= 20.4/204
= 0.1 mol.
• This is added to a 1 liter volumetric flask, add deionized water until near the fill line, stopper and mix
D.
Number of moles = molar concentration * volume
= 0.025 * 0.100
= 0.0025 mol
Equation for the reaction:
Ba(OH)2 + 2KHP --> Ba(KP)2 + 2H2O
1 mole of Ba(OH)2 reacted with 2 moles of KHP. By stoichiometry,
Number of moles of Ba(OH)2 = 0.0025/2
= 0.00125 mol.
Molarity = number of moles/volume
= 0.00125/0.01
= 0.125 M of Ba(OH)2.
Is there suppose to be a picture? Cause I do t see one
Answer:
The oxidation number of the metal decreases
2 Al + Fe₂O₃ → Al₂O₃ + 2 FeO
The metal element iron, is reduced from Fe⁺³ in Fe₂O₃ to Fe⁺² in FeO
Explanation:
When an element gains electron, the element becomes reduced, hence when a metal is reduced, the metal gains electrons, which reduces the oxidation number of the metal
An example of a metal being reduced is;
2 Al + Fe₂O₃ → Al₂O₃ + 2 FeO
In the above reaction, the iron (III) oxide is reduced to iron (II) oxide by aluminium metal.
Answer:
d) cut the large sized Cu solid into smaller sized pieces
Explanation:
The aim of the question is to select the right condition for that would increases the rate of the reaction.
a) use a large sized piece of the solid Cu
This option is wrong. Reducing the surface area decreases the reaction rate.
b) lower the initial temperature below 25 °C for the liquid reactant, HNO3
Hugher temperatures leads to faster reactions hence this option is wrong.
c) use a 0.5 M HNO3 instead of 2.0 M HNO3
Higher concentration leads to increased rate of reaction. Hence this option is wrong.
d) cut the large sized Cu solid into smaller sized pieces
This leads to an increased surface area of the reactants, which leads to an increased rate of the reaction. This is the correct option.
