Plz help me 10 points
2 answers:
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Answer:
66.6% (see below)
Step-by-step explanation:
Each sphere 4/3r²=4/3
(4²)=268.08cm³
Assuming the tube is the same width and height as the three spheres,
V=r²h=
(4²)24=1206.37
The three spheres are 268.08*3=804.24cm³
The tube is 1206.37cm³
<u>I’m not sure if your question is asking the percentage of the tube that’s filled, or the percentage that’s unfilled.</u>
Filled: 804.24÷1206.37=0.66666=66.6%
Unfilled: 1206.37-804.24=402.13
402.13÷106.37=0.33333=33.3%