Here's a trick.
Don't solve all the equations, you're given the answer to x so just substitute.
5/2*8+7/2=3/4*8+14
23.5=20 INCORRECT
5/4*8-9=3/2*8-21
1=-9 INCORRECT
5/4*8-2=3/2*8-4 <- YOUR ANSWER
8=8 CORRECT
Answer:
The absolute value function shows up in the world around us in many different areas. Suppose you are driving down the road and you look out your window and see a speed limit sign that says the speed limit is 50mph. You look at your speedometer and see that you're driving at 45mph, so you are going 5mph below the speed limit. Notice that even though you are going 5mph below the speed limit, we don't say you are going -5mph from the speed limit. We just state the difference from 50mph as a positive value. A road sign shows a vehicle's speed as the vehicle passes. SPEED LIMIT 30 YOUR SPEED Part A: The sign blinks for vehicles traveling within 5 mi/h of the speed limit. Write and solve an absolute value inequality to find the minimum and maximum speeds of an oncoming vehicle that will cause the sign to blink. Part B: Another sign blinks when it detects a vehicle traveling within 2 mi/h of a 35 mi/h speed limit. Write and solve an absolute value inequality to represent the speeds of the vehicles that cause the sign to blink.
Step-by-step explanation:
I am not that sure of my answer, however, I believe that the answer to your question is Yes, that it is assocaitive property
I don't know if its correct, but I hope this helps
3x² + 5x - 2 = 0
3x² + 6x - x - 2 = 0
3x(x) + 3x(2) - 1(x) - 1(2) = 0
3x(x + 2) - 1(x + 2) = 0
(3x - 1)(x + 2) = 0
3x - 1 = 0 or x + 2 = 0
+ 1 + 1 - 2 - 2
3x = 1 or x = -2
3 3 1 1
x = ¹/₃ or x = -2
f(x) = 3x² + 5x - 2
f(¹/₃) = 3(¹/₃)² + 5(¹/₃) - 2
f(¹/₃) = 3(¹/₉) + 1²/₃ - 2
f(¹/₃) = ¹/₃ - ¹/₃
f(¹/₃) = 0
(x, f(x)) = (¹/₃, 0)
f(x) = 3x² + 5x - 2
f(-2) = 3(-2)² + 5(-2) - 2
f(-2) = 3(4) - 10 - 2
f(-2) = 12 - 12
f(-2) = 0
(x, f(x)) = (-2, 0)
Vertical Asymptotes: ¹/₃ or -2
Horizontal Asymptotes: 0
Oblique Asymptote: No Asymptotes
Answer:
hello governor
Step-by-step explanation:
