Answer:
λ = 396.7 nm
Explanation:
For this exercise we use the diffraction ratio of a grating
d sin θ = m λ
in general the networks works in the first order m = 1
we can use trigonometry, remembering that in diffraction experiments the angles are small
tan θ = y / L
tan θ = 
= sin θ
sin θ = y / L
we substitute
= m λ
with the initial data we look for the distance between the lines
d = 
d = 1 656 10⁻⁹ 1.00 / 0.600
d = 1.09 10⁻⁶ m
for the unknown lamp we look for the wavelength
λ = d y / L m
λ = 1.09 10⁻⁶ 0.364 / 1.00 1
λ = 3.9676 10⁻⁷ m
λ = 3.967 10⁻⁷ m
we reduce nm
λ = 396.7 nm
Answer:
7.2V
Explanation:
Find the equivalent resistance:
Req = 10 ohms + 15 ohms = 25 ohms
Use ohm's law to find the current:
V = IR
12V = I(25 ohms)
I = .48 amps
Multiple the current with the value of R2 to get the voltage drop:
.48amps x 15 ohms = 7.2V
Answer:
Explanation:
3.75 * 10^-7
=3.75 * 1/10^7
=3.75/10000000
=3/800000000
any base which has it's power negative do it's reciprocal then the power will be positive.
Doubling the size of a load resistor increases the load current. Increasing the load resistance, in turn the total circuit resistance is reduced. The load current would not be half as much since when you increase the size of load resistor then load current increases.
