The mass of the aeroplane is 300,000 kg.
<h3>What is Newton's second law of motion?</h3>
It states that the force F is directly proportional to the acceleration a of the body and its mass.
The law is represented as
F =ma
where acceleration a = velocity change v / time interval t
Given is the aeroplane lands at a speed of 80 m/s. After landing, the aeroplane takes 28 s to decelerate to a speed of 10 m/s. The mean resultant force on the aeroplane as it decelerates is 750 000 N.
The force expression will be
F = mv/t
Substitute the values and we have
750000 = m x (80 -10)/ 28
750,000 = m x 2.5
m = 300,000 kg
Thus, the mass of the aeroplane is 300,000 kg.
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Given :
Initial velocity , u = 0 m/s .
Acceleration due to gravity on moon , 
.
Height , h = 2 m .
To Find :
Final position after falling for 1.5 seconds .
Solution :
We know , by equation of motion :
Here , 
.
So , equation will transform by :
Therefore , the height form moon's surface is 1.88 m .
Hence , this is the required solution .
Answer:
D. 371 N
Explanation:
Friction force equals normal force times the coefficient of friction:
F = Nμ
Since the ground is level, normal force equals weight:
N = mg
Therefore:
F = mgμ
F = (61 kg) (9.8 m/s²) (0.62)
F = 371 N
Answer:
Final velocity, v = 0.28 m/s
Explanation:
Given that,
Mass of the model, 
Speed of the model, 
Mass of another model, 
Initial speed of another model, 
To find,
Final velocity
Solution,
Let V is the final velocity. As both being soft clay, they naturally stick together. It is a case of inelastic collision. Using the conservation of linear momentum to find it as :
V = 0.28 m/s
So, their final velocity is 0.28 m/s. Hence, this is the required solution.
The magnitude of average current is 2.02 * 10⁻¹⁴ A.
<h3 /><h3>What is current?</h3>
A stream of charged particles, such as electrons or ions, travelling through an electrical conductor or a vacuum is known as an electric current. The net rate of electric charge flowing through a surface or into a control volume is how it is calculated.
Number of electrons passing per second = 4910/ 0.0662 = 74169.18
Number of proton passing per second = 3485/0.0662 = 52643.50
current due to electrons,
I = ne
= 74169.18 * 1.6 * 10⁻¹⁹
= 1.18 * 10⁻¹⁴ A
current due to protons,
I = ne
= 52643.50 * 1.6 * 10⁻¹⁹
= 0.84 * 10⁻¹⁴ A
total current I = Ie + Ip
I =( 1.18 + 0.84 ) * 10⁻¹⁴ A
I = 2.02 * 10⁻¹⁴ A
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