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Rudik [331]
3 years ago
6

H2S + CuSO4---> Complete the equation?

Chemistry
1 answer:
Eddi Din [679]3 years ago
6 0
H2S + CuSO4 → H2SO4 + CuS
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A petroleum-based lubricant used to in farming machinery.
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4 0
3 years ago
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The chemical equation, Cr + Fe(NO3)2 → Fe + Cr(NO3)3, is an example of which type of reaction?
Angelina_Jolie [31]

Answer:

Redox type

Explanation:

The reaction is:

2Cr +  3Fe(NO₃)₂ → 2Fe + 2Cr(NO₃)₃

2 moles of chromium can react to 3 moles of iron (II) nitrate in order to produce 2 moles of iron and 2 moles of chromium nitrate.

If we see oxidation state, we see that chromium changes from 0 to +3

Iron changed the oxidation state from +2 to 0

Remember that elements at ground state has 0, as oxidation state.

Iron is being reduced while chromium is oxidized. Then, the half reactions are:

Fe²⁺  +  2e⁻ ⇄  Fe    (Reduction)

Cr ⇄ Cr³⁺  +  3e⁻    (Oxidation)

When an element is being  reduced, while another is being oxidized, we are in prescence of a redox reaction.

8 0
3 years ago
What is the percent composition each element in c6h8o6
QveST [7]

Answer:

Percentage of oxygen = 30%

Percentage of carbon = 30%

Percentage of hydrogen = 40%

Explanation:

Formula:

Percentage of element = given amount / total amount × 100

Given compound:

C₆H₈O₆

Number of atoms of carbon = 6

Number of atoms of hydrogen = 8

Number of atoms of oxygen = 6

Total number of atoms = 20

Percentage of carbon = 6/20 × 100

Percentage of carbon = 30%

Percentage of Hydrogen = 8/20 × 100

Percentage of Hydrogen = 40%

Percentage of oxygen = 6/20 × 100

Percentage of oxygen = 30%

6 0
3 years ago
A buffer is composed of nh3 and nh4cl. How would this buffer solution control the ph of a solution when a small amount of a stro
Shkiper50 [21]

Answer:

According to Le-chatelier principle, equilibrium will shift towards left to minimize concentration of OH^{-} and keep same equilibrium constant

Explanation:

In this buffer following equilibrium exists -

NH_{3}(aq.)+H_{2}O(l)\rightleftharpoons NH_{4}^{+}(aq.)+OH^{-}(aq.)

So, OH^{-} is involved in the above equilibrium.

When a strong base is added to this buffer, then concentration of OH^{-} increases. Hence, according to Le-chatelier principle, above equilibrium will shift towards left to minimize concentration of OH^{-} and keep same equilibrium constant.

Therefore excess amount of OH^{-} combines with NH_{4}^{+} to produce ammonia and water. So, effect of addition of strong base on pH of buffer gets minimized.

5 0
4 years ago
HHHHHEEEELLLLLPPP PPPLLEEASEEE I GIVE BRAINLIEST!!!!!!!!!
svet-max [94.6K]
1. a. FeS + 2HCl --> FeCl2 + H2S
    b. This is a double- replacement reaction. (The elements "switch partners".)

2. a.2Na + F2 --> 2NaF
    b. This is a composition/synthesis reaction. (The two reactants are combining or synthesizing to make one product.)

3. a. 2HgO --> 2Hg + O2
    b. This is a decomposition reaction. (The single reactant is breaking down or "decomposing" into multiple reactants.)

4. Hydrogen gas reacts with oxygen gas to create water in a composition/synthesis reaction.

I hope these answers will help you! If you need any explanation, ask and hopefully I can get back to you. ;)
8 0
4 years ago
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