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dsp73
2 years ago
10

Plz answer this fast... will mark ur answer as brainliest

Chemistry
2 answers:
Xelga [282]2 years ago
7 0

Answer:

When fuels are incompletely burnt, they release carbon monoxide gas into the atmosphere. This gas is very dangerous as it is poisonous in nature

Explanation:

Nataly [62]2 years ago
7 0

Answer:

:they release carbon monoxide gas into the atmosphere. This gas is very dangerous as it is poisonous in nature

Explanation

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Classify the following as homogeneous or heterogeneous mixtures, or pure
victus00 [196]

Explanation:

Sugar -  Pure substance

Magnesium Ribbon - Pure Substance

Vegetable soup  Heterogeneous mixture

Bath oil - Homogeneous mixture

Tin of assorted biscuits - Heterogeneous mixture

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6 0
2 years ago
(e)
mars1129 [50]

Answer:36g

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x=68*3.6/6.8=36

5 0
3 years ago
Who discovered the nucleus?
Mama L [17]
Ernest Rutherford i believe
5 0
2 years ago
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¿como afecta la<br> temperatura el <br> volumen de un gas?
Oxana [17]

Lo afect porque cuando la temperature aumenta, el volumen aumentará, luego, cuando we mantiene la presión, es constante. Calentar el gas aumenta la emergía cinética we law partículas, lo que have que el gas se expanda.

Espero que esto ayude :)

8 0
2 years ago
sing any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 25.0°C for the following reaction
prisoha [69]

Answer:

2.76 × 10⁻¹¹  

Explanation:

I don’t have access to the ALEKS Data resource, so I used a different source. The number may be different from yours.

1. Calculate the free energy of formation of CCl₄

                         C(s)+ 2Cl₂(g)→ CCl₄(g)

ΔG°/ mol·L⁻¹:       0         0         -65.3

ΔᵣG° = ΔG°f(products) - ΔG°f(reactants) = -65.3 kJ·mol⁻¹

2. Calculate K

\text{The relationship between $\Delta G^{\circ}$ and K  is}\\\Delta G^{\circ} = -RT \ln K

T = (25.0 + 273.15) K = 298.15 K

\begin{array}{rcl}-65 300 & = & -8.314 \times 298.15 \ln K \\65300& = & 2479 \ln K\\26.34 & = & \ln K\\K& = & e^{26.34}\\&= & \mathbf{2.76 \times 10}^{\mathbf{11}}\\\end{array}

3 0
3 years ago
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