Sum of the angles of any quad =360
then y+(x+2)+(x-2)+(x-10) = y +3x -10 =360 (by adding both sides by 10)
y + 3x =370 ;.... eq 1
the sum of each two opposite sides in a quad inscribed in a circle =180
then (x+2)+(x-2)=180
therefore 2x =180
therefore x=90 (sub in eq 1)
y+3*90 =y +270 = 370 (subtracting both sides by 270)
therefore y=100
then measure angle B=100 degrees
A=92 degrees
C=88 degrees
D=80 degrees
$ 105
Suave gets $ 35 a day, but he realized he got $ 7 for every table he waited for.
= $ 35/7
= 5 .... He waited for 5 tables
which gets $ 7 for any table worth it
= 15 tables × $ 7
= $ 105
49.10 = 5 + 2.10 * x
x = 21