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3 years ago

Need help! Please answer quickly! :)

Mathematics

1 answer:

guapka [62]3 years ago

4 0

Answer: a

Step-by-step explanation:

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In one class the ratio of boys to girls is 5:6 if in this class it has 10 boys how much girls in this class

tigry1 [53]

Answer:

Step-by-step explanation:

5 : 6 = Number of boys to girls

(We have to ×2 to get from 5 to 10 so we must ×2 from 6 to 12)

10 : ? = Number of Boys to girls

10 : 12 = Number of Boys to girls

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3 years ago

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Alika [10]

Answer:

4 pi cm

Step-by-step explanation:

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3 years ago

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Find the slope of y = log ⁡ ( x^3 ) at x = 1.

romanna [79]

i'm pretty sure the slope is zero ...

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3 years ago

Two liters of water are poured into an empty vase shaped like an octagonal prism. The base area is 100 square centimeters. What

Molodets [167]

Answer: Height of the water is 20 cm.

Step-by-step explanation:

Since we have given that

Base area = 100 square cm

volume of vase shaped like an octogonal prism = 2 liters

We need to find the height of water.

and 1 liter = 1000 cm³

2 liters = 2×1000 cm³

As we know the formula for "Volume":

$Volume=\text{Base Area}\times height\\\\2\times 1000=100\times height\\\\height=\dfrac{2000}{100}\\\\height=20\ cm$

Hence, height of the water is 20 cm.

4 0

3 years ago

Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

$\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}$

7 0

2 years ago