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3 years ago

5

Find the domain of the function f of x equals square root of the quantity twelve x plus twenty four

1 answer:

Orlov [11]3 years ago

7 0

The domain is related to the x-value of the function. In this case, the goal of finding the domain is to make sure that the number under the radical sign is positive. The number that makes the function under the radical sign is -2. Hence this is the minimum number and the domain is from -2 to positive infinity.

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Klio2033 [76]

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3 years ago

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2 years ago

Find an equation of the line through (3,5) and parallel to y=3x+4

azamat

Answer:

y=3x-4

Step-by-step explanation:

slope = 3

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3 years ago

Find the points on the curve where the tangent is horizontal or vertical. If you have a graphing device, graph the curve to chec

klasskru [66]

Answer:

There is a horizontal tangent at (0,-4)

The tangent is vertical at (-2,-3) and (2,-3).

Step-by-step explanation:

The given function is defined parametrically by the equations:

$x=t^3-3t$

and

$y=t^2-4$

The tangent function is given by:

$\frac{dy}{dx}=\frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$\implies \frac{dy}{dx}=\frac{2t}{3t^2-3}$

The tangent is vertical at when $\frac{dx}{dt}=0$

$\implies \frac{3t^2-3}{2t}=0$

$\implies 3t^2-3=0$

$\implies 3t^2=3$

$\implies t^2=1$

$\implies t=\pm1$

When t=1,

$x=1^3-3(1)=-2$ and $y=1^2-4=-3$

When t=-1,

$x=(-1)^3-3(-1)=2$ and $y=(-1)^2-4=-3$

The tangent is vertical at (-2,-3) and (2,-3).

The tangent is horizontal, when $\frac{dy}{dx}=0$ or $\frac{dy}{dt}=0$

$\implies 2t=0$

$\implies t=0$

When t=0,

$x=0^3-3(0)=0$ and $y=0^2-4=-4$

There is a horizontal tangent at (0,-4)

5 0

3 years ago

What would be the best first step in solving 0.05x + 0.01 = 0.025? Explain.

ad-work [718]

Answer:

Step-by-step explanation:

it would be to subract 0.01 from 0.025 because you want to get the x by itself

4 0

3 years ago