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jekas [21]
3 years ago
13

Does anyone know ? thx

Mathematics
1 answer:
Natali5045456 [20]3 years ago
3 0
Answer:
4x-3
Explanation:
3x+2+x-5
4x-3
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Answer:

3.2

Step-by-step explanation:

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3 years ago
a grandmother deposits $6000 in an account that pays 9% compounded monthly. What will be the value of the account at the​ child'
valkas [14]

now, we're assuming she made the deposit at the child's birth, namely when year was 0, at the child's twenty-first birthday that'll be 21 years later.

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6000\\ r=rate\to 9\%\to \frac{9}{100}\dotfill &0.09\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &21 \end{cases} \\\\\\ A=6000\left(1+\frac{0.09}{12}\right)^{12\cdot 21}\implies A=6000(1.0075)^{252}\implies A\approx 39437.11

8 0
2 years ago
Find the size of angle x
madam [21]

Answer:

X=180-124

X=56

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8 0
3 years ago
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What happens to the value of the expression 150-j150−j150, minus, j as jjj decreases?
nikklg [1K]

Answer:

The value of the expression increases as j decreases

Step-by-step explanation:

Let f(j) = 150 - j150 - j150

f(j) = 150 - j300

As j decreases, the value of j300 decreases (i.e the farther j300 is from 150). Due to the wider gap between 150 and j300, the value of f(j) increases.

For example:

When j = 1, f(j) = 150 - (300*1) = -150

When j = 0.5, f(j) = 150 - (300*0.5) = 0

When j = 0. f(j) = 150 - (300*0) = 150

It is obvious from the analogy above that the expression 150-j150−j150 increases as j decreases

4 0
3 years ago
PLS HELPS!! THIS IS WORTH 200 PTS!! FIRST ONE ASNWERS CORRECTLY, GETS THE BRAINIEST.
Verizon [17]

Answer:

B) −2

Explanation:

When x is positive then y is positive integer.

When x is negative then y is negative integer.

<u>For Option A</u>

  • y = 2(-3) + 5
  • y = -1              [x is negative so is y]

<u>For Option B</u>

  • y = 2(-2) + 5
  • y = 1               [<u>x is negative</u> but <u>y is positive</u>]

<u>For Option C</u>

  • y = 2(1) + 5
  • y = 7               [x is positive so is y]

<u>For Option D</u>

  • y = 2(2) + 5
  • y = 9                [x is positive so is y]
8 0
2 years ago
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