Answer:
Step-by-step explanation:
9kg
The water level increases by 0.608 meters per minute when the water is 3.5 m deep
<h3>How to determine the rate?</h3>
The given parameters are:
- Radius, r = 3
- Height, h = 7
- Rate in, V' = 4.3m^3/min
The relationship between the radius and height is:
r/h = 3/7
Make r the subject
r = 3h/7
The volume of a cone is;

This gives

Expand

Differentiate

Make h' the subject

When the water level is 3.5.
We have:

Also, we have:
V' = 4.3
So, the equation becomes

Evaluate the products

Evaluate the quotient
h' = 0.608
Hence, the water level increases by 0.608 meters per minute
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17) f(x) = 16/(13-x).
In order to find domain, we need to set denominator expression equal to 0 and solve for x.
And that would be excluded value of domain.
13-x =0
Adding x on both sides, we get
13-x +x = x.
13=x.
Therefore, domain is All real numbers except 13.
18).f(x) = (x-4)(x+9)/(x^2-1).
In order to find the vertical asymptote, set denominator equal to 0 and solve for x.
x^2 -1 = 0
x^2 -1^2 = 0.
Factoring out
(x-1)(x+1) =0.
x-1=0 and x+1 =0.
x=1 and x=-1.
Therefore, Vertical asymptote would be
x=1 and x=-1
19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)
We have degrees of numberator and denominator are same.
Therefore, Horizontal asymptote is the fraction of leading coefficents.
That is 7/2.
20) f(x)=(x^2+3x-2)/(x-2).
The degree of numerator is 2 and degree of denominator is 1.
2>1.
Degree of numerator > degree of denominator .
Therefore, there would no any Horizontal asymptote.
Answer:
18.5÷11.99 is correct the answer is most likly option B