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____ [38]
3 years ago
5

A punter kicks a football into the air. The pathway of the football can be represented by the equation h=-16t^2+82t (where t= ti

me in seconds and h= height in feet.) what was the maximum height of the ball and what time was the maximum height reached?
Mathematics
2 answers:
Phantasy [73]3 years ago
8 0

Answer:64

Step-by-step explanation:

maxonik [38]3 years ago
7 0

Answer:

2fiftguvvbbhb to the following ad listing has ended on the same to ensure everyone I r

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PLZ HELPPP!!!!!!!!!! ASAP
salantis [7]

Answer:

They are consecutive terms in the Fibonacci Sequence.

Step-by-step explanation:

The sequence goes 1,1,2,3,5,8,13,21,...

Since 13 and 21 are consecutive here, that is the answer.

8 0
2 years ago
What is the volume of an cylinder shown below with radius of 11 and height of 12
den301095 [7]

Answer:

Step-by-step explanation:

your answer is 4,561.593

6 0
2 years ago
Simplify (5n^4)^-3. Assume n = 0.
denpristay [2]

Answer:

0

Step-by-step explanation:

5*0=0

0^4=0

0^-3=0

8 0
2 years ago
Read 2 more answers
A large game cube is wrapped with shrinkwrap. How many square inches of shrink wrap will be used to wrap five-game cubes?
Verdich [7]

Answer:

36

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm. The area of printed material on the po
grin007 [14]

Answer:

Dimensions of printed poster are

length is 32 cm

width is 48 cm


Step-by-step explanation:

Let's assume

length of printed poster is x cm

width of printed poster is y cm

now, we can find area of printed poster

so, area of printed poster is

=xy

we are given that area as 1536

so, we can set it to 1536

xy=1536

now, we can solve for y

y=\frac{1536}{x}

now, we are given

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm

so, total area of poster is

A=(8+x+8)\times (12+y+12)

A=(x+16)\times (y+24)

now, we can plug back y

A=(x+16)\times (\frac{1536}{x}+24)

now, we have to minimize A

so, we will find derivative

A'=\frac{d}{dx}\left(\left(x+16\right)\left(\frac{1536}{x}+24\right)\right)

we can use product rule

A'=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)

=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)

now, we can simplify it

A'=-\frac{24576}{x^2}+24

now, we can set it to 0

and then we can solve for x

A'=-\frac{24576}{x^2}+24=0

-\frac{24576}{x^2}x^2+24x^2=0\cdot \:x^2

-24576+24x^2=0

x=32,\:x=-32

Since, x is dimension

and dimension can never be negative

so, we will only consider positive value

x=32

now, we can solve for y

y=\frac{1536}{32}

y=48

so, dimensions of printed poster are

length is 32 cm

width is 48 cm


5 0
2 years ago
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