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____ [38]
3 years ago
5

A punter kicks a football into the air. The pathway of the football can be represented by the equation h=-16t^2+82t (where t= ti

me in seconds and h= height in feet.) what was the maximum height of the ball and what time was the maximum height reached?
Mathematics
2 answers:
Phantasy [73]3 years ago
8 0

Answer:64

Step-by-step explanation:

maxonik [38]3 years ago
7 0

Answer:

2fiftguvvbbhb to the following ad listing has ended on the same to ensure everyone I r

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A concert hall has three sections: the main floor, the balcony, and the gallery. For a recent concert, 1020 tickets were sold. T
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2. How comfortable are you working with proportions? (1 point)
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How comfortable are you writing this whole paragraph goddam I could never divide 100
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lisabon 2012 [21]

Step-by-step explanation:

The figure below shows a portion of the graph of the function j\left(x\right) \ = \ 4^{x-2}, hence the average rate of change (slope of the blue line) between the x and x+h is

                     \text{Average rate of change} \ = \ \displaystyle\frac{\Delta y}{\Delta x} \\ \\ \rule{3.7cm}{0cm} = \dsiplaystyle\frac{f\left(x+h\right) \ - \ f\left(x\right)}{\left(x \ + \ h \right) \ - \ x} \\ \\ \\  \rule{3.7cm}{0cm} = \displaystyle\frac{f\left(x + h\right) \ - \ f\left(x\right)}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x+h-2} \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x-2+h} \ - \ 4^{x-2}}{h}

                                                            \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h}\right) \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h} \ - \ 1 \right)}{h}

7 0
2 years ago
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