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drek231 [11]
3 years ago
7

What is the median test score? a)2.5 b)2 c)3 d)5

Mathematics
2 answers:
Xelga [282]3 years ago
7 0

Answer: The answer I got was A) 2.5

Step-by-step explanation:

Hope this Helps!!!

vovangra [49]3 years ago
3 0

Ok first of all fort nite is you know second I did some calculations its not five so the thing I cant find out is what 5.5  rounded is so what ever 5.5 rounded to is your answer so if you find out what 5.5 is rounded to youll have your answer! I hope this helps

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ad-work [718]
1.) 3+2=?  ?=5 brothers             2.) 54+9=?  ?=63 students              3.) 15-9=?  ?=4

4.) 60-20=?  ?=40 children        5.) 50-15=?  ?=35 trees          6.) 14+4=?  ?=18 times


Don't know why you needed help with this but ok.
5 0
3 years ago
a store sells 14 2/3 lb of carrots one day. The next day the store sells to 2 1/3 pounds of carrots how many pounds of carrots d
valentinak56 [21]

Answer:   17lbs of carrots

Step-by-step explanation:

8 0
3 years ago
Classify ABC by its sides. Then determine whether it is a right triangle.
m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

            AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

            AB = \sqrt{(9-3)^{2}+(6-3)^{2}  } = \sqrt{6^{2}+3^{2}  } =\sqrt{45}

Given vertices are  B(6,9) and C( 6,-3)

       B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

             =  \sqrt{(-3-9)^{2}+(6-6)^{2}  } =\sqrt{12^{2} } = 12

    BC = 12

Given vertices are  A(3,3) and C( 6,-3)

 AC = \sqrt{(6-3)^{2}+(-3-3)^{2}  } = \sqrt{9+36} = \sqrt{45}

AC² = AB²+BC²

45  = 45+144

 45  ≠ 189

∴Given Δ ABC is not a right angle triangle

 

5 0
3 years ago
Whats 1/7 + 3/4 ?<br> Please help me?
Katen [24]

Answer:

25/28

Step-by-step explanation:

28 is the greatest common factor, found by multiplying 7 by 4 (the denominators)

1/7 = 4/28

3/4 = 21/28

21/28 + 4/28 = 25/28

6 0
3 years ago
Read 2 more answers
Question 20
Alexxandr [17]

Answer:

The camera had to cover the greatest angle is CAMERA 3 because it had the largest angle of 71.47°

Step-by-step explanation:

From the above question,

We have:

Camera 1 = Angle A

Camera 2= Angle B

Camera 3 = Angle C

A = 210ft

B = 234ft

C = 260ft

We need to find Angle A( angle of camera 1) using the cosine rule

A=(B² + C² - 2BCCosA)

210² = 234² + 260² - 2 × 234 × 260 × CosA

210² = 122356 - 121680CosA

Square both sides

210² = 122356 - 121680CosA

44100 = 122356 - 121680CosA

121680CosA = 122356 - 44100

121680CosA = 78256

Cos A = 78256/121680

Cos A = 0.6431295201

A = arc cos (0.6431295201)

A = 49.974422249°

Angle A approximately = 49.97°

Using the Sine rule to find the Angle B

A/Sine A = B/Sine B

210ft/Sine 49.97° = 234ft/Sine B

210ft × Sine B = 49.97° × 234ft

Sine B =( Sine 49.97° × 234ft)/210ft

B = arc sin (0.8532172354)

Angle B = 58.56334

Approximately = 58.56°

Angle C = 180 - (49.97 + 58.56)°

Angle C = 71.47°

Therefore, the camera had to cover the greatest angle is Camera 3 because it had the largest angle of 71.47°

6 0
3 years ago
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