Answer:
First point - (0,-2)
second - (2,-1)
Third - ( 4, 0)
Step-by-step explanation:
Answer:
Find the area of a cardboard box with a length of 9 inches and a width of 4 inches.
Step-by-step explanation:
9 in × 4 in = 36 in²
we know that
The surface area of a cube is equal to
where
A is the area of one face of the cube
in this problem
Find the surface area
therefore
<u>the answer is</u>
of wrapping paper is needed to cover the box completely
Lets say N as cells
On monday N = 3
Multiply means that on tuesday is 9 cells and
Wednesday will 27 cells
Therefore N on wednesday is
No. of cells = 9n
The dimensions of the house should be 7 m by 13 m.
If the house is to be centered, we will take the same amount from the width as we do from the length of the lot for the dimensions. This gives us (10-x) and (16-x) as the dimensions.
The area of a rectangle is found by multiplying the length and width:
(10-x)(16-x) = 91
Multiplying the binomials we have:
10*16 - x*10 - x*16 -x*(-x) = 91
160 - 10x - 16x --x² = 91
160-10x-16x+x² =91
Combine like terms:
160-26x+x²=91
Rewrite this in standard form:
x²-26x+160=91
Subtract 91 from both sides:
x²-26x+160-91 = 91-91
x²-26x+69 = 0
Factoring this, we look for factors of 69 that sum to -26. -23*-3 = 69 and -23+-3 = -26, so:
(x-23)(x-3) = 0
Using the zero product property we know that either x-23=0 or x-3=0, so x=23 or x=3.
x was the amount we take off of the width and length of the lot; if we took 23m off of it, 10-23 gives us a negative amount, which is not realistic. This means both the width and length are subtracted by 3.
10-3 = 7 and 16-3 = 13.
These are the dimensions of the house.
