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sergiy2304 [10]
3 years ago
9

The fine structure for hydrogen atom is

Physics
1 answer:
pochemuha3 years ago
5 0

Answer:

When the familiar red spectral line of the hydrogen spectrum is examined at very high resolution, it is found to be a closely-spaced doublet. This splitting is called fine structure and was one of the first experimental evidences for electron spin.

Explanation:

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Which of these experiments tests a chemical property of an object??
Ilia_Sergeevich [38]
<span>B. shining a bright light on the objects and testing for decomposition </span> <span>      

In explanation, chemical property is a characteristic of a certain substance came from an outcome due to chemical change or reaction. In the situation above, more specifically toxicity is involved in the chemical property/change. Hence, when the object is tested for decomposition. Like for an example of decomposition simply in metals, rusting. Rusting a process of degeneration of metals. Here it works the same. Toxicity is how much damage did a certain entity do to the object. </span>



8 0
3 years ago
Read 2 more answers
Water pressurized to 3.5 x 105 Pa is flowing at 5.0 m/s in a horizontal pipe which contracts to 1/3 its former area. What are th
masha68 [24]

Answer:

the pressure after contraction is 2×10^5 Pa

the speed after contraction is 15m/s

Explanation:

We were given Pressure P to be 3.5 x 10^5 that is Flowing with speed of 5.0 m/s,

For us to calculate pressure we need to calculate the area first as;

Let initial Area = A₁

And Final area A₂

We were told that in a horizontal pipe it contracts to 1/3 its former area. Which means

A₂= A₁/3.................

V₁ is the speed

the pressure and speed of the water after the contraction can be calculated using equation of continuity below

A₂V₂ = A₁V₁

But

If we substitute given value in the expresion we have

V₂ = (3A *5)/A

V₂ = 15m/s

Therefore, the speed after contraction is 15m/s

Now we can calculate the pressure using

Bernoulli's equation

p₁ + ½ρv₁² + ρgh₁ = p₂ + ½ρv₂² + ρgh₂

But we know that the pipe is horizontal, then "h" terms cancel out then

p₁ + ½ρv₁² = p₂ + ½ρv₂²

Making P₂ subject of formula we have

p₂ = 0.5ρ( V ₁² - v₂² ) + P₁

P₂=. 0.5 × 1000 (5² -15² ) + 3*10^5

=2×10^5 Pa

Therefore, the pressure after contraction is 2×10^5 Pa

7 0
3 years ago
A 25 N force is used to push a box across a floor against a frictional force of 14 N. The box
Svetlanka [38]

Answer:

m = 44~Kg

Explanation:

<u>Net Force</u>

Newton's second law explains the dynamics principles when a number of forces are applied to an object.

The net force vector is the sum of the individual vector forces applied. The magnitude of the net force is related to the magnitude of the acceleration of the body as follows:

Fn=m.a

Furthermore, the acceleration can be calculated if we know the kinematic behavior of the body:

\displaystyle a=\frac{v_f-v_o}{t}

Where vf, vo, and t are the final speed, initial speed, and time, respectively.

The box is pushed across the floor with a force of 25 N against a frictional force of 14 N.

The net force applied to the box is:

Fn = 25 N - 14 N = 11 N

We also know the box is accelerated from rest (vo=0) to vf=4 m/s in t=16 seconds, thus:

\displaystyle a=\frac{4-0}{16}

a = 0.25~m/s^2

From the equation:

Fn=m.a

We solve for m:

\displaystyle m=\frac{Fn}{a}=\frac{11~N}{0.25~m/s^2}

\mathbf{m = 44~Kg}

3 0
3 years ago
In certain ranges of a piano keyboard, more than one string is tuned to the same note to provide extra loudness. For example, th
diamong [38]

Answer:

3.77 Hz

Explanation:

The beat frequency that is heard can be calculated using the following equation:

f_{b} = f_{1} - f_{2}

<u>Where:</u>

f₁ = 110 Hz

f_{2} = \frac{f_{1}}{\sqrt{\frac{T_{1}}{T_{2}}}}

<u>With:</u>

<em>T₁ = 594 N        </em>

<em>T₂ = 554 N </em>

f_{2} = \frac{f_{1}}{\sqrt{\frac{T_{1}}{T_{2}}}} = \frac{110 Hz}{\sqrt{\frac{594 N}{554 N}}} = 106.23 Hz

Hence, the beat frequency is:        

f_{b} = f_{1} - f_{2} = 110 Hz - 106.23 Hz = 3.77 Hz      

Therefore, the beat frequency that is heard when the hammer strikes the two strings simultaneously is 3.77 Hz.

I hope it helps you!                              

3 0
4 years ago
The speed of light inside a medium is (2.0 x 10^8m/s) What is the index of refraction (n) of the medium?
kondor19780726 [428]

Answer:

Refractive index of a medium = Speed of light in vacuum/Speed of light in a medium

1.5 = 3 x 108 / Speed of light in medium

Speed of light in the medium = 3 x 108 /1.5

= 2 x 108 m/s.

Explanation:

3 0
2 years ago
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