The correct answer is
<span>the flux increases because the magnitude of b increases.
In fact, the magnetic flux is given by
</span>
<span>Where B is the intensity of the magnetic field, A the area enclosed by the coil and </span>
the angle between the direction of B and the perpendicular to the area A.
We can see that since in the problem the intensity of B increases, and the direction remains unchanged, then the magnetic flux increases as well.
Answer:
E(final)/E(initial)=2
Explanation:
Applying the law of gauss to two parallel plates with charge density equal σ:
So, if the charge is doubled the Electric field is doubled too
E(final)/E(initial)=2
Solution :
The relationship between the strength of magnetic field and the radiusof a charged particle's path is obtained through Newton's second law, which is given by :
F = ma
F = qvB and 
Substituting these values in the second law of Newton,
Now solving for B, we get:
= 0.261 T
The field strength can be obtained by using the technology of today.
Answer: The height (position) of the ball and the acceleration due gravity
Explanation:
In this case we are taking about gravitational potential energy, which is the energy a body or object possesses, due to its position in a gravitational field. In this sense, this energy depends on the relative height of an object with respect to some point of reference and associated with the gravitational force.
In the case of the Earth, in which the gravitational field is considered constant, the gravitational potential energy 
will be:
Where:
is the mass of the ball
is the acceleration due gravity (assuming the ball is on the Earth surface)
is the height (position) of the ball respect to a given point
Note the value of the gravitational potential energy is directly proportional to the height.
