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olga nikolaevna [1]
3 years ago
14

What is the force of gravity on an object known as?

Physics
1 answer:
pshichka [43]3 years ago
7 0
"Gravity force" (also known as "weight")
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Which situation shows potential energy transforming into kinetic energy 1.A car stopped at a stoplight 2.A flowerpot falling fro
Troyanec [42]

Answer:

2.A flowerpot falling from a balcony

Explanation:

Potential energy is the internal energy within a body at rest or at a height above the ground. In this case of the falling flowerpot, the flowerpot initially has a potential energy due to its position on the balcony above the surface of the earth. As the flowerpot falls, the work done against gravity in taking the flowerpot to this height on the balcony (equivalent to the potential energy) is transformed into the kinetic energy of motion as the flowerpot falls down through the height.

7 0
3 years ago
A 100 Ω resistive heater in a tank of water (1kg) increases its temperature from 10°C to 20°C over a period of 1 hour. During th
Nookie1986 [14]

Answer:48.52 kJ

Explanation:

Given

Resistance=100 \Omega

temperature increases from 10^{\circ}C to 20^{\circ}C

Voltage=50 V

Heat given(H)=\frac{V^2t}{R}

Where V=voltage applied

t=time

R=Resistance

H=\frac{50^2\times 60\times 60}{100}=90 kJ

Heat absorbed by water is

Q=mc(\Delta T)

where

m=mass of water

c=specific heat of water

\Delta T=change in temperature

Q=1000\times 4.184\times (20-10)=41.48 kJ

Therefore  90-41.48=48.52 kJ is not absorbed by water and leaves the system into the surroundings.

8 0
3 years ago
A 2.0 kg puck is at rest on a level table. It is pushed straight north with a constant force of 5N for 1.50 s and then let go. H
lukranit [14]

Answer:

d = 6.32 m

Explanation:

Given that,

The mass of a puck, m = 2 kg

It is pushed straight north with a constant force of 5N for 1.50 s and then let go.

We need to find the distance covered by the puck when move from rest in 2.25 s.

We know that,

F = ma

a=\dfrac{F}{m}\\\\a=\dfrac{5}{2}\\\\a=2.5\ m/s^2

Let d is the distance moved in 2.25 s. Using second equation of motion,

d=ut+\dfrac{1}{2}at^2\\\\d=0+\dfrac{1}{2}\times 2.5\times (2.25)^2\\\\d=6.32\ m

So, it will move 6.32 m from rest in 2.25 seconds.

4 0
3 years ago
Riders on a ferris wheel move in a circle with a speed of 4.0 m/s. As they go around, they
Vanyuwa [196]
Answer: D = 16m

Explanation: given values: a = 2 m/s2, v = 4 m/s
In this case we have to determine the diameter of the Ferris wheel.
Diameter of circle is given as: D = 2.r.
First we have to find radius of wheel. The best way to find that is using the centripetal acceleration equation: a = v2/r
Plug in values in above equation to find radius: 2 m/s2 = (4 m/s)2/r 2 m/s2 = (16 m2/s2)/r r = (16 m2/s2)/2 m/s2
r = 8.0m
Diameter of Ferris wheel is:
D = 2.r.
D = 2.8m
D = 16m
6 0
3 years ago
Which of these is an example of a physical change?
Daniel [21]
Grinding pepper is a physical change
8 0
3 years ago
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