The correct choice would be 128.

If there are 6 options and the person can pick any number of toppings, we need to know the number of subsets that can be formed with 6. That would be 2^6 or 64.

Since there is a pan or hand-tossed option, we need to multiply 64 by 2 to find the total.
64 x 2 = 128

8 0

3 years ago

Explain why P(A|D) and P(D|A) from the table below are not equal. A 4-column table has 3 rows. The first column has entries A, B

dangina [55]

Answer:

P(A|D) and P(D|A) from the table above are not equal because P(A|D) = $\frac{2}{10}$ and P(D|A) = $\frac{2}{8}$

Step-by-step explanation:

Conditional probability is the probability of one event occurring with some relationship to one or more other events

P(A|D) is called the "Conditional Probability" of A given D

P(D|A) is called the "Conditional Probability" of D given A

The formula for conditional probability of P(A|D) = P(D∩A)/P(D)

The formula for conditional probability of P(D|A) = P(A∩D)/P(A)

The table

↓ ↓ ↓

: C : D : Total

→ A : 6 : 2 : 8

→ B : 1 : 8 : 9

→Total : 7 : 10 : 17

∵ P(A|D) = P(D∩A)/P(D)

∵ P(D∩A) = 2 ⇒ the common of D and A

- P(D) means total of column D

∵ P(D) = 10

∴ P(A|D) = $\frac{2}{10}$

∵ P(D|A) = P(A∩D)/P(A)

∵ P(A∩D) = 2 ⇒ the common of A and D

- P(A) means total of row A

∵ P(A) = 8

∴ P(D|A) = $\frac{2}{8}$

∵ P(A|D) = $\frac{2}{10}$

∵ P(D|A) = $\frac{2}{8}$

∵ $\frac{2}{10}$ ≠ $\frac{2}{8}$

∴ P(A|D) and P(D|A) from the table above are not equal

5 0

4 years ago

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