How do I figure out a mixed percentage number of a whole

Four yardequal Blank feet

jonny [76]

1 yard = 3 feet

3 * 4 = 12

So 4 yards is equal to 12 feet.

3 0

3 years ago

Read 2 more answers

A. What is the explicit definition for this sequence? b. How far does she run on day 19?

creativ13 [48]

Answer:

(a) $a_n=1+\frac{1}{6}(n-1)$

(b) 4 miles

Step-by-step explanation:

Given:

The sequence of run is an arithmetic sequence.

Miles traveled on day 1 = 1 mile

Miles traveled on day 7 = 2 miles

(a).

Explicit formula for an arithmetic sequence is given as:

$a_n=a_1+(n-1)d\\a_n\to n^{th}\ term\\a_1\to first\ term\\n\to number\ of\ terms\\d\to \textrm{common difference}$

Here, $a_1=1,a_7=2$

So,

$a_7=a_1+(7-1)d\\2=1+6d\\6d=2-1\\d=\frac{1}{6}$

Therefore, the explicit definition of the above sequence is given as:

$a_n=1+\frac{1}{6}(n-1)$

Where, $a_n$ is the miles covered on $n^{th}$ day.

(b)

In order to find the distance covered by her on day 19, we plug in 19 for n in the above formula. This gives,

$a_{19}=1+\frac{1}{6}(19-1)\\\\a_{19}=1+\frac{1}{6}(18)\\\\a_{19}=1+3=4\ mi$

Therefore, the number of miles covered by her on day 19 is 4 miles.

3 0

3 years ago

F(x)=5x-1 Domain {-1,0,1,2} Find the range:

Katena32 [7]

Answer:

Step-by-step explanation:

Putting the values in F(x)=5x-1

= -6,-1,5,9

Range =highest -lowest =9--6

=15

3 0

3 years ago

Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments

kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

$\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}$

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

$\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}$

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0

1 year ago

Substitute x+y =200 9.5x+27y=4000

Vera_Pavlovna [14]

Point form: (80,120)
X=80, Y=120

3 0

3 years ago