How do I figure out a mixed percentage number of a whole

Mathematics

1 answer:

seraphim [82]3 years ago

7 0

Sorry not in high school

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What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−23x+5

kotykmax [81]

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = intercept

m = slope

The equation of the given line is

y = - 23x+5

Comparing it with the slope intercept equation, slope, m = -23

If a line is perpendicular to another line, the slope of the line is the negative reciprocal of the given line. This means that the slope of the line passing through the point (8, 1) is 1/23

We would determine the intercept, c by substituting m = 1/23, x = 8 and y = 1 into y = mx + c. It becomes

1 = 1/23 × 8 + c

1 = 8/23 + c

c = 1 - 8/23 = 15/23

The equation becomes

y = x/23 + 15/23

7 0

3 years ago

What is the center of the circle X2 + y2 = 28+ 3x?

notka56 [123]

Answer:

The center is $(\frac{3}{2},0)$ .

The problem:

What is the center of the circle X2 + y2 = 28+ 3x?

Step-by-step explanation:

We need to put anything with an $x$ together and anything with a $y$ together:

$x^2+y^2=28+3x$

Subtract $3x$ on both sides:

$(x^2+y^2)-3x=(28+3x)-3x$

$x^2-3x+y^2=28$

We need to complete the square for $x$ 's. The $y$ 's are already done.

Keep in mind: $x^2+bx+(\frac{b}{2})^2=(x+\frac{b}{2})^2So we are going to add [tex](\frac{-3}{2})^2$ on both sides so we can use this identity for the left side with the $x$ 's: