HELP ME PLEASEEEEEEEEEEEEEEEE
1 answer:
Answer:
522 m^2
Step-by-step explanation:
I've circles the numbers that you actually need to solve this problem.
First, find the area of the bigger rectangle by multiplying the length and width.
24*21=504
Then find the area of the smaller rectangle the same way
3*6=18
then add them to get the total area
504+18=522
522 m^2
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Answer:
Part a) The expression is
Part b) Customer cannot buy 2.5 ounces of paprika and have it shipped for less than $8.00
Step-by-step explanation:
<u><em>The complete question is</em></u>
A spice store charged 2.75 for 25 grams of paprika. It also charges 5% of the purchase price for shipping any order.
Part a) Write and simplify an expression to determine the cost of buying and shipping x ounces of paprika. Use 1 ounce = 28 grams
Part b) Can a customer buy 2.5 ounces of paprika and have it shipped for less than 8.00? Explain
step 1
Convert grams to ounces
Remember that
To convert grams to ounces divide by 28
The unit price is
Let
x ----> the number of ounces of paprika
y ----> the cost of buying and shipping x ounces of paprika
5%=5/100=0.05
Part b) For x=2.5 oz
substitute in the equation
therefore
Customer cannot buy 2.5 ounces of paprika and have it shipped for less than $8.00
Answer:
The correct options are;
EFGH has 4 congruent sides
Diagonal FH bisects angles EFG and EHG
Angle FEH is congruent to angle FGH
Step-by-step explanation:
1) Given that for a reflection, we have;
The distance of the reflected preimage from the line of reflection = The distance of the reflected image from the line of reflection
Therefore;
The distance of the point E from the line HF = The distance of the point G from the line HF
Also the reflection of an preimage (x, y) about the x-axis, gives an image (x, -y)
We can show that from the length of a line given by the equation, that the length EH ≅ GH and EF ≅ GF
Therefore since we are given that EH = EF, we have;
EH = GH = GF = EF by the definition of congruency, which gives 4 congruent sides
2) Given that EH = GH = GF = EF and HF = FH by reflective property, we have;
ΔEHF ≅ ΔGHF
∴ ∠GHF ≅ ∠EHF by Congruent Parts of Congruent Triangles are Congruent
Similarly, ∠GFH ≅ ∠EFH
Therefore, ∠GFH = ∠EFH and ∠GHF = ∠EHF
Therefore, diagonal FH bisects angles EFG and EHG
3) Given that ΔEHF ≅ ΔGHF, we have;
Angle FEH is congruent to angle FGH, by Congruent Parts of Congruent Triangles are Congruent