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Serjik [45]
3 years ago
8

The value of y varies directly with x. When y = 3.5, x = 2. What is the value of y when x is 16?

Mathematics
1 answer:
AveGali [126]3 years ago
4 0
In order to do this problem, you have to divide 16 by 2 to see how many times x was multiplied. you would find that x was multiplied 8 times, so in order to find y, you would multiply 3.5 eight times.

y = 28 when x = 16
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If a < 0 and b > 0, then the point (a, b) is in Quadrant
Archy [21]

Answer: The answer is C) lll.

A) I.  

B) II.  

C) III.  

D) IV.

Step-by-step explanation:

If a < 0 and b < 0, then the point (a, b) is in Quadrant

7 0
3 years ago
How many different 10 person committees can be selected from a pool of 23 people?
Salsk061 [2.6K]

We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.

We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.

Formula for combination:

C(n,r)=\dfrac{n!}{(n-r)!r!}

Where n represents the number of objects/people in the set and r represents the number of objects/people being chosen from the set

There are 23 people in the set and 10 people being chosen from the set

C(23,10)=\dfrac{23!}{(23-10)!10!}

=\dfrac{23!}{13!\times10!}

Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

=1,144,066

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!

~ Padoru

4 0
3 years ago
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In AOPQ, o = 700 cm, p = 840 cm and q=620 cm. Find the measure of _P to the<br> nearest degree
Westkost [7]

Given:

In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.

To find:

The measure of angle P.

Solution:

According to the Law of Cosines:

\cos A=\dfrac{b^2+c^2-a^2}{2bc}

Using Law of Cosines in triangle OPQ, we get

\cos P=\dfrac{o^2+q^2-p^2}{2oq}

\cos P=\dfrac{(700)^2+(620)^2-(840)^2}{2(700)(620)}

\cos P=\dfrac{490000+384400-705600}{868000}

\cos P=\dfrac{168800}{868000}

On further simplification, we get

\cos P=0.19447

P=\cos^{-1}(0.19447)

P=78.786236

P\approx 79

Therefore, the measure of angle P is 79 degrees.

8 0
3 years ago
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Find the x-intercepts, use the zero product property, r(r+7)=0
UkoKoshka [18]

9514 1404 393

Answer:

  r = 0

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Step-by-step explanation:

There is no x in the equation, hence there are no x-intercepts.

__

If we assume you want the values of r that satisfy the equation, the zero product property tells you they will be the values that make the factors zero.

The factors are r and (r+7).

The factor r is zero when ...

  r = 0

The factor (r+7) is zero when ...

  r +7 = 0   ⇒   r = -7

The "x-intercepts" are r=0 and r=-7.

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Jet001 [13]

Answer:

the function shows growth of a factor of 2

Step-by-step explanation:

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