<em>1 Cancel m.</em>
12i=c*m/s
<em>2 Use rule a*b/c = ab/c</em>
12i=cm/s
<em>3 Multiply both sides by s.</em>
12is=cm
<em>4 Divide both sides by 12.</em>
is=cm/12
<em>5 Divide both sides by i</em>
s=cm/12/i
<em>6 Simplify cm/12/i</em>
s=sm/12i
Answer:
m(m-3)=108
Step-by-step explanation:
Complete question below:
Two positive integers are 3 units apart on a number line. Their product is 108.
Which equation can be used to solve for m, the greater integer?
m(m – 3) = 108
m(m + 3) = 108
(m + 3)(m – 3) = 108
(m – 12)(m – 9) = 108
Solution
On the number line,
Let
m= larger integer
The integers are 3 numbers apart on the number line, so
m-3=smaller integer
The product (×) of the larger and smaller integers=108
(m)*(m-3)=108
m(m-3)=108
Therefore, the equation that can be used to solve for m, the larger integer is:
m(m – 3) = 108
(-1,6)(2,-6)
slope = (-6 - 6) / (2 - (-1) = -12/3 = -4
y = mx + b
slope(m) = -4
(-1,6)...x = -1 and y = 6
sub and find b, the y int
6 = -4(-1) + b
6 = 4 + b
6 - 4 = b
2 = b
so the equation is : y = -4x + 2 <=== here is one
y - y1 = m(x - x1)
slope(m) = -4
(-1,6)...x1 = -1 and y1 = 6
sub
y - 6 = -4(x - (-1) =
y - 6 = -4(x + 1) <=== here is one
y - y1 = m(x - x1)
slope(m) = -4
(2,- 6)...x1 = 2 and y1 = - 6
sub
y - (-6) = -4(x - 2) =
y + 6 = -4(x - 2) .... here is one, but it is not an answer choice
