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Free_Kalibri [48]
3 years ago
9

The two

Mathematics
1 answer:
taurus [48]3 years ago
5 0

Answer:

x = 5

Step-by-step explanation:

Sides of large triangle: 4x and 15

Corresponding sides of small triangle: 3x + 1 and 12

\dfrac{4x}{15} = \dfrac{3x + 1}{12}

60 \times \dfrac{4x}{15} = 60 \times \dfrac{3x + 1}{12}

16x = 15x + 5

x = 5

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Find the sum of 2/5 and 3/10
mash [69]
Answer: 7/10

Explanation:

Find the common denominator:

Since 2/5 and 3/10 has a common of denominator of ten, solve.

2/5 + 3/10 = 2/5 * 2/2 = 4/10 + 3/10 = 7/10

Therefore, the sum of 2/5 + 3/10 = 7/10
3 0
3 years ago
Read 2 more answers
In a poultry farm, 50 hens give 200 eggs in 2 days. In how many days will 20 hens give 400 eggs?.
romanna [79]

The number of days is 10 if, on a poultry farm, 50 hens give 200 eggs in 2 days.

<h3>What is the ratio?</h3>

It is described as the comparison of two quantities to determine how many times one obtains the other. The proportion can be expressed as a fraction or as a sign: between two integers.

It is given that:

On a poultry farm, 50 hens give 200 eggs in 2 days.

It is required to find the number of days will 20 hens require to give 400 eggs:

Let x be the number of days:

(50×2)/200 = (20x)/400

x = 10

Thus, the number of days is 10 if, on a poultry farm, 50 hens give 200 eggs in 2 days.

Learn more about the ratio here:

brainly.com/question/13419413

#SPJ4

7 0
2 years ago
The two box plots summarize the number of hours spent in the weight room for all the players on the football team
iragen [17]

Options:

A. Players at school 1 typically spent more time in the weight room than players at school 2.

B. The middle half of the data for school 1 has more variability than the middle half of the data for school 2.

C. The median hours spent in the weight room for school 1 is less than the median for school 2 and the interquartile ranges for both schools are equal.

D. The total number of hours spent in the weight room for players at school 2 is greater than the total number of hours for players at school 1.

(See attachment for the box plots)

Answer:

C. The median hours spent in the weight room for school 1 is less than the median for school 2 and the interquartile ranges for both schools are equal.

Step-by-step explanation:

The median for school 1 is the value at the vertical line that divides the box of the box plot display of for school 1, which is 8

School 2 has a median of 9.

As we can see, the median for school 1 is less than the median of school 2.

Interquartile range is the range of the box.

Interquartile range for school 1 = 10 - 4 = 6

Interquartile range for school 2 = 13 - 6 = 6

As we can also see, the interquartile range for school 1 and that of school 2 are equal.

7 0
4 years ago
A right cylinder has a diameter of 10 in and height of 15 in. Find the surface area of the cylinder.
Step2247 [10]

Answer:

628.32 in.²

Step-by-step explanation:

Height: 15 in.

Diameter: 10 in.

Radius: 5 in.

A = 2πrh + 2πr²

2 · π · 5 · 15 + 2 · π · 5²

≈ 628.32

6 0
3 years ago
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Someone, please do all my answers I really do not get anything!
Marianna [84]
I can’t see anything but a black paper
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3 years ago
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