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faust18 [17]
3 years ago
9

Classify the triangle based on side lengths 5, 15, 19.

Mathematics
2 answers:
lutik1710 [3]3 years ago
8 0
I'm pretty sure it's obtuse

AlekseyPX3 years ago
7 0
I think it's Acute i hope it's right.


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What is the area of the circle shown? Use 3.14 to approximate pi. Round your answer to the nearest hundredth. ​
leva [86]

Answer:

452.16

Step-by-step explanation:

12^2 x 3,14

5 0
3 years ago
F(2/9) if f(x)=3x+1/3
Harman [31]

Answer:

1

Step-by-step explanation:

4 0
3 years ago
What is the value of X that makes equation true? -5(2x - 3) + 4x = -3x + 6
Alisiya [41]

Answer:

x=3

Step-by-step explanation:

6 0
3 years ago
Can someone please explain how to get the answer I've watched multiple videos on implicit derivatives and I still cant figure it
Arisa [49]

We're given the implicit equation

x² + 2x + y² - 4y = 12

where "implicit" means that one of the variables is considered a function of the other. In this case, the variable y = y(x) depends on the value of the variable x - in other words, the possible values of y are implied by the value of x. We then say that this equation defines y as an implicit function of x.

We're also given the implicit derivative,

dy/dx = (-2x - 2)/(2y - 4)

which tells us the rate of change y as a function of both x and y. The value of dy/dx corresponds to the slope of the tangent line to the curve defined by the implicit equation above at some point (x, y).

The tangent line is horizontal when its slope is zero. This happens when

(-2x - 2)/(2y - 4) = 0

If y ≠ 2, then we can eliminate the denominator and we're left with

-2x - 2 = 0

Solve for x :

-2x = 2

x = -1

This tells us that the points on the curve with x-coordinate -1 have a tangent line to the curve that is horizontal.

The tangent line is vertical when its slope is undefined/infinite, or equivalently when the denominator of dy/dx is zero:

2y - 4 = 0

Solve for y :

2y = 4

y = 2

So any point on the curve with y-coordinate 2 will have a tangent line there that is vertical.

By completing the square in the implicit equation, we can easily identify where these points are located.

x² + 2x + y² - 4y = 12

x² + 2x + 1 + y² - 4y + 4 = 17

(x + 1)² + (y - 2)² = 17

This equation defines a circle centered at (-1, 2) with radius √17. When x = -1, we have

(y - 2)² = 17   ⇒   y = 2 ± √17

and when y = 2, we have

(x + 1)² = 17   ⇒   x = -1 ± √17

See the attached plot to see the circle and the tangents at these points.

7 0
2 years ago
Solve 12|x|−7=8. Does anyone know how to do this?<br>​
Travka [436]

Answer:

8+8=16/12

x=16/12, 4/3

4 0
3 years ago
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