Generally, you are told to approach these by "clearing fractions". That is, you generally multiply the equations by the least common denominator so all fractions and mixed numbers become integers.
Alternatively, you can simply do the arithmetic using the numbers given. You learned a long time ago how to add, subtract, multiply, and divide mixed numbers and fractions. Do these operations as necessary to solve the equations.
The point with the greatest distance to the origin is given by:
B. (-3, 3).
<h3>What is the distance between two points?</h3>
Suppose that we have two points, 
and 
. The distance between them is given by:
The origin is given by point (0,0), hence the distance of a point (x,y) to the origin is given by:
D = sqrt(x² + y²).
Hence the distances for each point given in the problem are:
- A. Distance = sqrt((-4)² + (-1)²) = sqrt(17).
- B. Distance = sqrt((-3)² + (3)²) = sqrt(18).
- C. Distance = sqrt((4)² + 0²) = sqrt(16).
- D. Distance = sqrt((2)² + 3²) = sqrt(13).
Hence option B has the greatest distance.
More can be learned about the distance between two points at brainly.com/question/18345417
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4y - 20.......u need to find a common factor that can go into 4y and 20.....the only common factor is 4. So u can factor that out.....4 goes into 4 one time (but do not forget the y) and 4 goes into 20 five times....4(y - 5)
4(y - 5)...u can also check ur answer by distributing the 4 through the parenthesis and getting 4 * y - 4 * 5 = 4y - 20
Answer:
a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4
Step-by-step explanation:
for the equation
(1 + x⁴) dy + x*(1 + 4y²) dx = 0
(1 + x⁴) dy = - x*(1 + 4y²) dx
[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx
∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx
now to solve each integral
I₁= ∫[1/(1 + 4y²)] dy = 1/2 *tan⁻¹ (2*y) + C₁
I₂= ∫[-x/(1 + x⁴)] dx
for u= x² → du=x*dx
I₂= ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ = - tan⁻¹ (x²) +C₂
then
1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C
for y(x=1) = 0
1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C
since tan⁻¹ (1²) for π/4+ π*N and tan⁻¹ (0) for π*N , we will choose for simplicity N=0 . hen an explicit solution would be
1/2 * 0 = - π/4 + C
C= π/4
therefore
1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4
