Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
________________________________
now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
The observatory telescope has 22 times the magnifying power compared to the small telescope.
Data;
- small telescope = 150 times
- large telescope = 3300
<h3>Division of Numbers</h3>
To solve this question, we have to divide the large telescope by the small telescope to calculate it's magnifying power.
The magnification of the observatory telescope is 22 times greater or larger than the small telescope.
Learn more on division of numbers here;
brainly.com/question/7068223
Consecutive interior theorem
X+96+96+x= 180
2x+192=180
2x= -12
X=-6
Students total 43430
5742 students more
43430-5742=37688
37688/2 = 18844
ANSWER
Country 1 : 18,844 students
Country 2 : 24,586 students
Explanation: By taking away the 5742 students you set them off to the side. Leaving you with a new sum. You then divide the sum by the number of countries (2). Add the remainder of the students to one of the countries.
Answer:
{x,y} = {-1,-10/7}
Step-by-step explanation:
