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Ivenika [448]
3 years ago
13

I neeed help with middle school math

Mathematics
2 answers:
Artist 52 [7]3 years ago
6 0
Multiple different forms in the picture attached - for these problems use Math-way is super easy
First is the exact form

dexar [7]3 years ago
5 0

Answer:

22/5*8/3

176/15

yep that's it

I think..

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A basket has y+10 apples, they are divided equally between 5 kids. How many apples did every kid get?​
mezya [45]

Answer:

15+10=15

Step-by-step explanation:

6 0
3 years ago
4 lb. 8 oz. − 1 lb. 2 oz. =
saw5 [17]
4.8 takeaway 1.2 equals 3.6
8 0
3 years ago
Read 2 more answers
A ball has a volume of 4 cubic inches (in3). Use the fact that 1 inch is equal to 2.54 cm to convert this volume to cubic centim
Marina86 [1]

Answer:

V = 65.548 cm³

Step-by-step explanation:

We have,

Volume of a ball is 4 cubic inches or 4\ \text{inch}^3.

We know that, 1 inch = 2.54 cm

It is required to convert this volume to cubic centimetre or \text{cm}^3.

4\ \text{inch}^3=4\ \text{inch}^3\times (\dfrac{2.54\ \text{cm}}{1\ \text{inch}})^3\\\\V=65.548\ \text{cm}^3

So, the volume of the ball is 65.548 cm³.

7 0
3 years ago
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
3 years ago
In your biology class, your final grade is based on several things: a lab score, scores on two major tests, and your score on th
balu736 [363]

Answer:

72.7 is the weighted average score

Step-by-step explanation:

The weighted average score

= score of lab * % share of total grade + score of first major test  * % share of total grade + score of second major test  * % share of total grade + Score of the final exam  * % share of total grade

Substituting the given values, we get -

0.23 * 74 + 0.25 * 69 + 0.25 * 62 + 0.27 * 85

= 72.7

3 0
3 years ago
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