The function of mordant in the gram staining is to expose grams positive cell to the decolorizer which dissolves the lipids in the cell wall thus allowing the crystals violent-iodine to leach out of the cell. This facilitate the cell subsequently be stained by with safranin.
<span>an oxide of iron, magnesium, aluminum, and chromium</span>
Answer:
-43.3 °C
Explanation:
To find the temperature, you need to use the Ideal Gas Law equation. The equation looks like this:
PV = nRT
In this formula,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas Law constant (0.08206 atm*L/mol*K)
-----> T = temperature (K)
By plugging the given values into the equation and simplifying, you can find the temperature. After you get a temperature, you need to convert it into Celsius.
P = 2.88 atm R = 0.08206 atm*L/mol*K
V = 3.76 L T = ? K
n = 0.574 moles
PV = nRT
(2.88 atm)(3.76 L) = (0.574 moles)(0.08206 atm*L/mol*K)T
10.8288 = (0.04710244)T
230. K = T
Kelvin - 273.15 = Celsius
230 K - 273.15 = -43.3 °C
A) electrolyte the others either describe a process, the opposite, or a whole different thing
Answer:
Boiling point: 63.3°C
Freezing point: -66.2°C.
Explanation:
The boiling point of a solution increases regard to boiling point of the pure solvent. In the same way, freezing point decreases regard to pure solvent. The equations are:
<em>Boiling point increasing:</em>
ΔT = kb*m*i
<em>Freezing point depression:</em>
ΔT = kf*m*i
ΔT are the °C that change boiling or freezing point.
m is molality of the solution (moles / kg)
And i is Van't Hoff factor (1 for I₂ in chloroform)
Molality of 50.3g of I₂ in 350g of chloroform is:
50.3g * (1mol / 253.8g) = 0.198 moles in 350g = 0.350kg:
0.198 moles / 0.350kg = 0.566m
Replacing:
<em>Boiling point:</em>
ΔT = kb*m*i
ΔT = 3.63°C/m*0.566m*1
ΔT = 2.1°C
As boiling point of pure substance is 61.2°C, boiling point of the solution is:
61.2°C + 2.1°C = 63.3°C
<em>Freezing point:</em>
ΔT = kf*m*i
ΔT = 4.70°C/m*0.566m*1
ΔT = 2.7°C
As freezing point is -63.5°C, the freezing point of the solution is:
-63.5°C - 2.7°C = -66.2°C