If 45 g of O2 gas in a 500 mL container is exerting a pressure of 5.2 atm, 22.53K is the temperature in the gas.
<h3>What is an ideal gas equation?</h3>
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
First, calculate the moles of the gas using the gas law,
PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.
Given data:
P= 5.2 atm
V= 500 mL =0.5 L
n=?
R= 
T=?
Moles = 1.40625
Putting value in the given equation:
T= 22.53167034 K= 22.53K
Hence, If 45 g of O2 gas in a 500 mL container is exerting a pressure of 5.2 atm, 22.53K is the temperature in the gas.
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The normal atomic orbitals are joined mathematically during the process of hybridization to create new atomic orbitals known as hybrid orbitals. Even if hybrid orbitals are not identical to regular atomic orbitals.
<h3>What are atomic orbitals?</h3>
Atomic theory & quantum mechanics use the mathematical concept of a "atomic orbital" to describe the location and wavelike behavior of an electron within an atom. Each of those orbitals can contain a maximum of electron pairs, each with a unique spin quantum number s.
<h3>How are atomic orbitals calculated?</h3>
Within every of an atom's shells, various orbital combinations can be found. The n=1 shell has just s orbitals; the n=2 shell contains s and p orbitals; the n=3 shell contains s, p, and d orbitals; and the n=4 up shells include all four types of orbitals.
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First, write out a complete balanced reaction for the combustion of ethane, ethane + O2 -> CO2 + H20. Then, divide the grams of ethane by its Molar Mass and multiply by 32, the molar mass of O2.
Answer:
Explanation:
Here's where all that equation balancing is going to come into use. Since the main object of the question is not the equation, I'm just going to balance it and use it.
4Fe + 3O2 ====> 2Fe2O3
Step One
Find the number of mols of O2 in 24.9 grams of O2
1 mol O2 = 2*16 = 32 grams
x mol O2 = 24.9 grams Cross multiply
32x = 24.9 * 1 Divide by 32
x = 24.9/32
x = 0.778 moles of O2
Step Two
Type the findings under the balanced equations parts. Solve for the number of moles of Fe
4Fe + 3O2 ====> 2Fe2O3
x 0.778
Step Three
Set up the proportion
4/x = 3/0.778 Cross multiply
Step Four
Solve the proportion moles of Fe
4*0.778 = 3x
3.112 = 3x Divide by 3
3.112/3 = 3x/3
x = 1.037 moles of Fe
Step Five
Find the mass of Fe
1 mol Fe = 56 grams
1.037 mol Fe = x Cross Multiply
x = 56*1.037
x = 58.1 grams
