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3 years ago

See attached photo!! Please help Asap!!! CORRECT ANSWERS ONLY!! THANKS IN ADVANCE!!

Mathematics

1 answer:

Lelu [443]3 years ago

7 0

Answer:

C. construction of a perpendicular to a line through a given external point

Step-by-step explanation:

The crossing arcs below the line are equidistant from the marked points on the line (J and K), and those are equidistant from point A. If we call the point of intersection of those crossing arcs point X, we know that AX is a perpendicular bisector of JK.

However, J and K are not part of the "given" of this construction. Rather, they are the result of the first step of drawing arcs centered at A. So the fact that AX bisects JK is not important. What is important is that AX is perpendicular to the line and goes through the given point A.

This is a partially-completed construction of a perpendicular to a line through the given external point A.

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Is y=2x+3 proportional

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Step-by-step explanation:

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Step-by-step explanation:

parallelogram area is:h×base

10×14=140

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2 years ago

When adding or subtracting fractions with like denominators , does the denominator change ?

mrs_skeptik [129]

Answer:

No, the denominator doesn't change when adding or subtracting fractions.

Step-by-step explanation:

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3 years ago

Help!! Solving absolute value inequalities

goblinko [34]

Answer:

48. $x \geq -7$ or $x \leq 31$

51. $x \leq 13$ or $x \geq 3$

54. $x < \frac{5}{2}$ or $x > \frac{-15}{2}$

57. $x < \frac{18}{7}$ or $x > -4$

Step-by-step explanation:

48. $| 12 - x | \leq 19$

-There are two equations:

Equation 1:

$12 - x \leq 19$

Equation 2:

$12 - x \geq -19$

Solving equation 1:

$12 - x \leq 19$

$12- 12 - x \leq 19 - 12$

$-x \leq 7$

$\frac{-x}{-1} \leq \frac{7}{-1}$

$x \geq -7$ (Inequality sign changed, because of dividing by a negative number)

-Solving equation 2:

$12 - x \geq -19$

$12 - 12 - x \geq -19 - 12$

$-x \geq -31$

$\frac{-x}{-1} \geq \frac{-31}{-1}$

$x \leq 31$ (Inequality sign changed, because of dividing by a negative number)

-Answers:

$x \geq -7$ or $x \leq 31$

51. $| x - 8 | \leq 5$

-There are two equations:

Equation 1:

$x - 8 \leq 5$

Equation 2:

$x - 8 \geq - 5$

-Solving equation 1:

$x - 8 \leq 5$

$x - 8 + 8 \leq 5 + 8$

$x \leq 13$

-Solving equation 2:

$x - 8 \geq - 5$

$x - 8 + 8 \geq - 5 + 8$

$x \geq 3$

Answers:

$x \leq 13$ or $x \geq 3$

54. $| 4x + 10 | < 20$

-There are two equations:

Equation 1:

$4x + 10 < 20$

Equation 2:

$4x + 10 > -20$

-Solving equation 1:

$4x + 10 < 20$

$4x + 10 - 10 < 20 - 10$

$4x < 10$

$\frac{4x}{4} < \frac{10}{4}$

$x < \frac{5}{2}$

-Solving equation 2:

$4x + 10 > -20$

$4x + 10 - 10 > -20 - 10$

$4x > -30$

$\frac{4x}{4} > \frac{-30}{4}$

$x > \frac{-15}{2}$

-Answers:

$x < \frac{5}{2}$ or $x > \frac{-15}{2}$

57. $| 7x + 5 | < 23$

-There are two equations:

Equation 1:

$7x + 5 < 23$

Equation 2:

$7x + 5 > -23$

-Solving equation 1:

$7x + 5 < 23$

$7x + 5 - 5 < 23 - 5$

$7x < 18$

$\frac{7x}{7} < \frac{18}{7}$

$x < \frac{18}{7}$

Solving equation 2:

$7x + 5 > -23$

$7x + 5 - 5 > -23 - 5$

$7x > -28$

$\frac{7x}{7} > \frac{-28}{7}$

$x > -4$

Answers:

$x < \frac{18}{7}$ or $x > -4$

And we are finished.

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5 0

3 years ago

Find the maximum and the minimum value of the following objective function, and the value of x and y at which they occur. The f

kumpel [21]

Answer:

The maximum value of the objective function is 112 when x = 0 and y = 7.

Step-by-step explanation:

Given the constraints:

5x+3y≤37, 3x+5y≤35, x≥0, y≥0

Plotting the above constraints using geogebra online graphing tool, we get the solution to the constraints as:

A(0, 7), B(7.4, 0), C(5, 4) and D(0, 0)

The objective function is given as E =2x+16y, therefore:

At point A(0, 7): E = 2(0) + 16(7) = 112

At point B(7.4, 0): E = 2(7.4) + 16(0) = 14.8

At point C(5, 4): E = 2(5) + 16(4) = 74

At point D(0, 0): E = 2(0) + 16(0) = 0

Therefore the maximum value of the objective function is at A(0, 7).

The maximum value of the objective function is 112 when x = 0 and y = 7.

8 0

2 years ago