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DENIUS [597]
3 years ago
13

Keshawn is asked to compare and contrast the domain and range for the two functions.

Mathematics
2 answers:
Lapatulllka [165]3 years ago
8 0

Answer: The correct option is 'The domain of both functions is all real numbers'.

Step-by-step explanation:

Here, functions are f(x) = 5x and g(x) =5x

Since the domain of f(x) is, D= { x : x belongs to all real numbers.}

Therefore, Domain of f(x) is all real numbers.

Since f(x) and g(x) have the same value,

Therefore, Domain of g(x) is also the set of real numbers.

Now, range of f(x) is , R=  { 5x : x belongs to all real numbers.}

Therefore, Range of f(x) is all real numbers.

⇒ Range of g(x) is also all real numbers.

So, we can say by the above explanation, only option (1) is correct.


Artemon [7]3 years ago
3 0
The correct answer for the question that is being presented above is this one: "4. The range of both functions is y > 5; <span>1. The domain of both functions is all real numbers.</span>" Keshawn is asked to compare and contrast the domain and range for the two functions. f(x) = 5x; g(x) = 5x.
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Responses:

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<h3>Methods by which the above responses are obtained</h3>

Background information;

The question relates to the coordinate system with the abscissa represent the real number and the ordinate representing the imaginary number.

Solution:

If A is in quadrant I; A = a + b·i

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c·A = c·a + c·b·i

Therefore;

c·a is negative

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Multiplying <em>A</em> by negative scalar if <em>A</em> is in quadrant II, we have;

c·A = -c·a + c·b·i

-c·a is positive

c·b·i is negative

Therefore;

c·A = -c·a + c·b·i is in <u>quadrant IV</u>

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A = a + b·i

a is negative

b is negative

Multiplying <em>A</em> with a negative scalar <em>c</em> gives;

c·A = c·a + c·b·i

c·a is positive

c·b  is positive

Therefore;

  • c·A = c·a + c·b·i is in<u> quadrant I</u>

Learn more about real and imaginary numbers here;

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