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DENIUS [597]
3 years ago
13

Keshawn is asked to compare and contrast the domain and range for the two functions.

Mathematics
2 answers:
Lapatulllka [165]3 years ago
8 0

Answer: The correct option is 'The domain of both functions is all real numbers'.

Step-by-step explanation:

Here, functions are f(x) = 5x and g(x) =5x

Since the domain of f(x) is, D= { x : x belongs to all real numbers.}

Therefore, Domain of f(x) is all real numbers.

Since f(x) and g(x) have the same value,

Therefore, Domain of g(x) is also the set of real numbers.

Now, range of f(x) is , R=  { 5x : x belongs to all real numbers.}

Therefore, Range of f(x) is all real numbers.

⇒ Range of g(x) is also all real numbers.

So, we can say by the above explanation, only option (1) is correct.


Artemon [7]3 years ago
3 0
The correct answer for the question that is being presented above is this one: "4. The range of both functions is y > 5; <span>1. The domain of both functions is all real numbers.</span>" Keshawn is asked to compare and contrast the domain and range for the two functions. f(x) = 5x; g(x) = 5x.
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Given :

The foci of hyperbola are (8,0) and (-8,0) .

The difference of the focal radii = 6.

To Find :

The equation of the hyperbola.

Solution :

We know, distance between foci is given by :

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Also, difference between the foci or focal distance is given by :

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Now, we know for hyperbola :

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General equation of hyperbola is :

\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\\\\\dfrac{x^2}{9}+ \dfrac{y^2}{55}=1

Hence, this is the required solution.

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3 years ago
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Answer:

The following histogram shows the relative frequencies of the height recorded to the nearest inch of population of women the mean of the population is 64.97 inches and the standard deviation is 2.66 inches

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0.22268

Step-by-step explanation:

z-score is z = (x-μ)/σ,

where x is the raw score

μ is the population mean

σ is the population standard deviation.

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The probability that the selected woman will have a height of at least 67 inches is 0.22268

Step-by-step explanation:

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3 years ago
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