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3 years ago

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Keshawn is asked to compare and contrast the domain and range for the two functions.

2 answers:

Lapatulllka [165]3 years ago

8 0

Answer: The correct option is 'The domain of both functions is all real numbers'.

Step-by-step explanation:

Here, functions are f(x) = 5x and g(x) =5x

Since the domain of f(x) is, D= { x : x belongs to all real numbers.}

Therefore, Domain of f(x) is all real numbers.

Since f(x) and g(x) have the same value,

Therefore, Domain of g(x) is also the set of real numbers.

Now, range of f(x) is , R= { 5x : x belongs to all real numbers.}

Therefore, Range of f(x) is all real numbers.

⇒ Range of g(x) is also all real numbers.

So, we can say by the above explanation, only option (1) is correct.

Artemon [7]3 years ago

3 0

The correct answer for the question that is being presented above is this one: "4. The range of both functions is y > 5; <span>1. The domain of both functions is all real numbers.</span>" Keshawn is asked to compare and contrast the domain and range for the two functions. f(x) = 5x; g(x) = 5x.

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Please help. Will give Brainliest.

san4es73 [151]

Answer:

x = 0

x = 7/5

x = -2/3

Step-by-step explanation:

x2 =0

x=0

5x -7 =0

5x = 7

x = 7/5

3x+2 =0

3x = -2

x = -2/3

These are all the 3 roots of this equation

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3 years ago

Raheem made a net of a triangular pyramid as shown.

Cerrena [4.2K]

Answer:

the answer is b

Step-by-step explanation:

i took the test it is b. The sum of the areas of faces A, B, and C.

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2 years ago

Find the length of BC.

Murrr4er [49]

Answer:

C, 53.68 units

Step-by-step explanation:

tan 54° = $\frac{x}{39}$

39 tan 54° = x

x= 53.6788949 (just plug it in a scientific or graphing calculator)

x≈53.68

4 0

2 years ago

Abby's friend told her that he drew a quadrilateral with exactly one pair of parallel sides. Abby said it must be a trapezoid. I

Ratling [72]

Answer:

Yes, she is correct

Step-by-step explanation:

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2 years ago

Read 2 more answers

Use a graphing utility to graph the function and the damping factor of the function in the same viewing window.

Bas_tet [7]

Answer:

The function touches the damping factor

at x= $\frac{(4n-3)\pi}{2}$ and x= $\frac{(4n-1)\pi}{2}$

The x-intercept of f(x) is

at x= $n\pi$

Step-by-step explanation:

Given function is f(x)= $e^{-3x} sin(x)$ and damping factor as y= $e^{-3x}$ and y= $(-1)e^{-3x}$

To find when function touches the damping factor:

For f(x)= $e^{-3x} sin(x)$ and y= $e^{-3x}$

Equating the both the equation,

$e^{-3x} sin(x)=e^{-3x}$

$sin(x)=1$

x= $\frac{(4n-3)\pi}{2}$

For f(x)= $e^{-3x} sin(x)$ and y= $(-1)e^{-3x}$

Equating the both the equation,

$e^{-3x} sin(x)=(-1)e^{-3x}$

$sin(x)=(-1)$

x= $\frac{(4n-1)\pi}{2}$

Therefore, The function touches the damping factor x= $\frac{(4n-3)\pi}{2}$ and x= $\frac{(4n-1)\pi}{2}$

To find x-intercept of f(x):

For x-intercept, y=0

f(x)= $e^{-3x} sin(x)$

y= $e^{-3x} sin(x)$

$e^{-3x} sin(x)=0$

Hence, $e^{-3x}$ is always greater than zero.

Therefore, $sin(x)=0$

x= $n\pi$

Thus,

The x-intercept of f(x) is at x= $n\pi$

7 0

3 years ago