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igor_vitrenko [27]
3 years ago
10

Two cups of coffee, one that is at 10 C and one that is 20 C, are mixed. Which statement about the temperature of the mixture is

correct?
Chemistry
2 answers:
Alenkasestr [34]3 years ago
8 0
The temperature will be the average of 10 C and 20 C which is 15 C.
Energy is transferred from faster moving molecules to slower moving molecules, and the result is the average of 15°C. <span>This is just another temperature problem where you add something hot to a cold liquid and you have to calculate the final temperature. Since the energy given up by the hot coffee = energy absorbed by the cold coffee, the mass of the two fluids is the same (each is 1 cup) and both are coffee so the specific heat is the same, you get T hot - Tfinal = Tfinal - Tcold and then you solve it, you get T final = (T hot + Tcold) / 2 which is simply the average of the hot and cold temperatures.

BRAINLIEST PLS!</span>
GenaCL600 [577]3 years ago
7 0

Answer: it’s C!!

Explanation:

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3 years ago
A chemist requires 5.00 liters of 0.420 M H2SO4 solution. How many grams of H2SO4 should the chemist dissolve in water? 129 gram
natali 33 [55]

Answer:

Approximately 206 grams.

Explanation:

How many moles of sulfuric acid \mathrm{H_2SO_4} are there in this solution?

\text{Number of moles of solute} = \text{Concentration} \times \text{Volume}.

The unit for concentration "\mathrm{M}" is equivalent to mole per liter. In other words, \rm 1\;M = 1\; mol\cdot L^{-1}. For this solution, the concentration of \mathrm{H_2SO_4} is \rm 0.420\;M = 0.420\; mol\cdot L^{-1}.

\begin{aligned}n(\mathrm{H_2SO_4}) &= c(\mathrm{H_2SO_4}) \cdot V\\&= \rm 0.420\;mol\cdot L^{-1}\times 5.00\; L \\&= \rm 2.10\; mol\end{aligned}.

What's the mass of that \rm 2.10\; mol of \mathrm{H_2SO_4}?

Start by finding the molar mass M of \mathrm{H_2SO_4}.

Relative atomic mass data from a modern periodic table:

  • H: 1.008;
  • S: 32.06;
  • O: 15.999.

\displaystyle M(\mathrm{H_2SO_4}) = 2\times \underbrace{1.008}_{\mathrm{H}} + 1\times \underbrace{32.06}_{\mathrm{S}} + 4\times \underbrace{15.999}_{\mathrm{O}} = \rm 98.072\;g\cdot mol^{-1}.

\text{Mass} = \text{Quantity in moles} \times \text{Molar Mass}.

m = n \cdot M = \rm 2.10\; mol \times 98.072\;g\cdot mol^{-1} \approx 206\; g.

In other words, the chemist shall need approximately 206 grams of \mathrm{H_2SO_4} to make this solution. As a side note, keep in mind that the 206 grams of \mathrm{H_2SO_4} also take up considerable amount of space. Therefore it will take less than 5.00 L of water to make the 5.00 L solution.

6 0
4 years ago
Help pls <br> is this direct, constant, indirect, or cycling?
IRISSAK [1]

Answer:

Indirect. I don't think it's cycling and it's not direct or constant

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