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3 years ago

Find the mass of 175.4mL of benzene if the density is 0.8786g/ml

1 answer:

5 0

Hey there!:

Volume = 175.4 mL

density = 0.8786 g/mL

mass = ?

Therefore:

D = m / V

0.8786 = m / 175.4

m = 0.8786 * 175.4

m = 154.10644 g

hope this helps!

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A gene is a to a chromosome as

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I believe the answer would be A. A pea is to a pod

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3 years ago

How many electrons would be transferred in either a voltaic or electrolytic cell that uses the following half reactions

omeli [17]

Answer:

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

Explanation:

$Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V$

$Mg^{2+}(aq) + 2 e^- \rightarrow Mg (s),E^o = -2.37 V$

The substance having highest positive reduction $E^o$ potential will always get reduced and will undergo reduction reaction.

Reduction : cathode

$Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V$ ..[1]

Oxidation: anode

$Mg(s)\rightarrow Mg^{2+}(aq) + 2 e^-,E^o = 2.37 V$ ..[2]

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}$

$E^o_{cell}=-0.036V-(-2.37 V)=2.334 V$

The overall reaction will be:

2 × [1] + 3 × [2] :

$2Fe^{3+} (aq) + 3Mg(s)+6e^-\rightarrow 2Fe (s)+3Mg^{2+}(aq)+6e^-$

Electrons on both sides will get cancelled :

$2Fe^{3+} (aq) + 3Mg(s)\rightarrow 2Fe (s)+3Mg^{2+}(aq)$

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

5 0

3 years ago

Draw a molecular model of sulfur trioxide.

bija089 [108]

Answer:

Here's what I get

Explanation:

The Lewis structure of SO₃ consists of a central sulfur atom double-bonded to each of three oxygen atoms that points to the corners of an equilateral triangle.

A ball-and-stick model of SO₃ is shown below.

6 0

3 years ago

A 0.2688 g sample of a monoprotic acid neutralized 16.4 mL of 0.08133 M KOH solution. Calculate the molar mass of the acid

ivanzaharov [21]

Answer:

202 g/mol

Explanation:

Let's consider the neutralization between a generic monoprotic acid and KOH.

HA + KOH → KA + H₂O

The moles of KOH that reacted are:

0.0164 L × 0.08133 mol/L = 1.33 × 10⁻³ mol

The molar ratio of HA to KOH is 1:1. Then, the moles of HA that reacted are 1.33 × 10⁻³ moles.

1.33 × 10⁻³ moles of HA have a mass of 0.2688 g. The molar mass of the acid is:

0.2688 g/1.33 × 10⁻³ mol = 202 g/mol

3 0

2 years ago

37.9 grams of an unknown substance undergoes a temperature increase of

jenyasd209 [6]

Answer:

1.023 J / g °C

Explanation:

m = 37.9 grams

ΔT = 25.0*C

H = 969 J

c = ?

The equation relating these equation is;

H = mcΔT

making c subject of formulae;

c = H / mΔT

c = 969 J / (37.9 g * 25.0*C)

Upon solving;

c = 1.023 J / g °C

4 0

2 years ago