Question

For the polynomial x^3-7x^2+12x-6, 1 is a zero. Express g(x) as a product of linear factors.

Answer 1

Answer:

(x–1)(x²–6x+6)

Explanation:

Given that 1 is a zero, we can use synthetic division to compute the factor.

If 1 is a zero (x–1) is a factor.

Here is the process:

| 1 | 1 -7 12 -6

↓ +(1) +(-6) +(6)

↓ ↓ ↓

1 -6 6 0

→ [1]x² + [-6]x + [6]1 + [0]/x–1 =

x² – 6x + 6.

Therefore the factors are (x–1)(x²–6x+6)