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tamaranim1 [39]
3 years ago
7

For the polynomial x^3-7x^2+12x-6, 1 is a zero. Express g(x) as a product of linear factors.

Mathematics
1 answer:
Liula [17]3 years ago
6 0

Answer:

(x–1)(x²–6x+6)

Explanation:

Given that 1 is a zero, we can use synthetic division to compute the factor.

If 1 is a zero (x–1) is a factor.

Here is the process:

| 1 | 1 -7 12 -6

↓ +(1) +(-6) +(6)

↓ ↓ ↓

1 -6 6 0

→ [1]x² + [-6]x + [6]1 + [0]/x–1 =

x² – 6x + 6.

Therefore the factors are (x–1)(<u>x²–6x+6</u>)

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Y = 1/4x 
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A bag contains 10 pounds of dog food. A family feeds their dogs 0.85 pound of dog food a day. How much dog food is left in the b
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A bag contains 10 pounds of dog food.

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3 years ago
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Factor: 8ab - 16ac + 12a
aksik [14]
The GCF we factor out is 4a

8ab = 4a*2b
16ac =  4a*4c
12a = 4a*3

Each term has been factored so that 4a is a factor

Using those factorizations, we can use the distributive property in reverse
8ab - 16ac + 12a = 4a*2b - 4a*4c + 4a*3
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Answer is choice A<span />
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The number 64 has the property that it is divisible by its units digit. How many whole numbers between 10 and 50 have this prope
sineoko [7]

Answer:

\large \boxed{17}

Step-by-step explanation:

Let's call the numbers "<em>tu</em>", where<em> t</em> is the tens digit and <em>u</em> is the units digit.

We can solve this by the "brute force" method —  examining each number to see if it satisfies the conditions.

\begin{array}{cccl}\mathbf{u}&\mathbf{tu}& \textbf{Divisible by u} & \\0 &20, 30, 40 & 0 & \text{Division by zero is impossible}\\1 & 11, 21, 31, 41 & 4& \text{All numbers are divisible by one}\\2 & 12, 22, 32, 42 & 4 & \text{All even numbers are divisible by two}\\3 & 13,  23, 33, 43 & 1 &\text{Only 33 is divisible by three}\\4 & 14, 24, 34, 44 & 2 & \text{Only 24 and 44 are divisible by four}\\5 & 15, 25, 35, 45 & 4 & \text{Numbers ending in 5 are divisible by five}\\\end{array}

\begin{array}{cccl}6 & 16, 26, 36, 46 & 1 & \text{Only 36 is divisible by six}\\7 & 17, 27, 37, 47 & 0 & \text{None of the numbers is divisible by seven}\\8 & 18, 28, 38, 48 & 1 & \text{Only 48 is divisible by eight}\\9 & 19, 29, 39, 49 & 0 & \text{None of the numbers is divisible by nine}\\& \textbf{TOTAL =} &\mathbf{17}& \\\end{array}\\\text{$\large \boxed{\mathbf{17}}$ numbers between 10 and 50 are divisible by their units digit}

5 0
3 years ago
The ratio of boys to girls at the dance was 8 to 4. How many girls were at the dance if there were 88 boys at the dance?
nevsk [136]

88/8=11.

So multiply 4 by 11.

4x11=44

So the ratio is 88:44.

There are 44 girls at the dance

---

hope it helps

5 0
3 years ago
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