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Brrunno [24]
3 years ago
15

Frank gives a box of books a push to the right, which makes it slide across his

Physics
1 answer:
valina [46]3 years ago
3 0

Answer:

C

Explanation:

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Which image shows both potential and kinetic energy?
Natasha2012 [34]

Answer:

The one in the middle

Explanation: i listened to the other person and i got it wrong, this is the answer for edge2020 sience review on energy!!!!

trust me its the middle one!!!!!

And everyone if ur not sure, like 100% sure about an answer dont answer at all cuz for 1: ur taking up a spot for others to answer. for 2: you could make people wrong. And for 3: its annoying. And 4: it makes stuff like this happen!

<u>NOT ARGUEING IM JUST PUTTING MY THOUGHTS AND OPINIONS OUT THERE ;)</u><em> many thanks.</em>

4 0
3 years ago
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Calculate 8 ∙ 10^-4 divided by 2 ∙ 10^2.
Digiron [165]
8 ∙ 10^-4 / 2 ∙ 10^2 = (8/2) ∙ ((10^-4)*(10^-2)) = <span>4 ∙ 10^-6</span>
7 0
3 years ago
I’m sorry this is a quiz and we’re correcting it and I still don’t get it anyone know ?
kotegsom [21]

Answer:

3.0M

Explanation:

Thats two wavelengths,not one.

Pretty honest mistake I would've made the same if I was rushing

5 0
3 years ago
A wire has a current density of 6.25 × 10 6 A / m 2 6.25×106 A/m2 . If the cross-sectional area of the wire is 1.79 mm 2 1.79 mm
joja [24]

Answer:17.44A

Explanation: Current density=I/Area

Area is given by 2.79mm^2=2.79×10^-6m^2

Current=I=current density ×Area=6.25×10^6 ×2.79×10^-6=17.44A

3 0
3 years ago
A firecracker in a coconut blows the coconut into three pieces. two pieces of equal mass fly off south and west, perpendicular t
kirill [66]

As per momentum conservation theory

If net force on a system is zero then initial momentum of the system will be equal to final momentum of that system.

Since initially coconut is at rest so initial momentum is zero

Here it break into three pieces such that two parts of same mass while third part is of double mass

now we can say

P_1 + P_2 + P_3 = 0

here we know that two parts fly off with same speed v0 along south and west directions

mv_0 (-\hat j) + mv_0 (-\hat i) + 2m \vec v = 0

now we will have

\vec v = \frac{v_0}{2}\hat i + \frac{v_0}{2}\hat j

so here magnitude of the speed of the third part will be

|v| = \sqrt{(\frac{v_0}{2})^2+(\frac{v_0}{2})^2}

|v| = \frac{v_0}{\sqrt2}

and the direction of the third part will be along North East direction

7 0
3 years ago
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