Identify the kinds of notes and rest found in the following musical lines.

How did rutherford’s experiment shape our current model of the atom?

marissa [1.9K]

Answer:

Explanation:

Before the Rutherford's model of the atom, the plum pudding model proposed by J.J Thomson through his experiment using the gas discharge tube was the prevalent structure of the atom known.

Through Thomson, it was widely and popularly believed that the atom is made up of a pool of negatively charged particles.

When Rutherford performed the Alpha scattering experiment using a thing gold foil, he observed that all the alpha particles passed through the thin gold foil and just a few of them were deflected back.

To explain this, the suggested the atomic or nuclear model of that atom in which an atom has a small positively charged center called nucleus where all the mass is concentrated.

Today, the suggestion that an atom is made up of nucleus is highly relevant and still consistent.

6 0

4 years ago

!Select ALL and ANY that apply!

BaLLatris [955]

Nuclear Reactor is made to use the energy which is released due to nuclear fission reaction.

These chain reactions are very fast and they are used with some components which can control these reactions otherwise these reaction will start with high rate and could not be controlled after that.

In order to control these reactions we need to control the high energy particles which can stimulate these reactions

These are neutrons which act as catalyst of these nuclear reactions and these reactions can be control by controlling the numbers of neutrons

These neutrons can be absorbed by some mechanism and the rods which are used to absorb these high energy neutrons are known as control rods.

So correct answer must be control rods

8 0

4 years ago

Read 2 more answers

Block 1, of mass m1 = 2.70 kg , moves along a frictionless air track with speed v1 = 27.0 m/s . It collides with block 2, of mas

ki77a [65]

Answer:

a) Block 1 = 72.9kgm/s

Block 2 = 0kgm/s

b) vf = 1.31m/s

c) ∆KE = 936.36Joules

Explanation:

a) Momentum = mass× velocity

For block 1:

Momentum = 2.7×27

= 72.9kgm/s

For block 2:

Momentum = 53(0) (body is initially at rest)

= 0kgm/s

b) Using the law of conservation of momentum

m1u1+m2u2 = (m1+m2)v

m1 and m2 are the masses of the block

u1 and u2 are their initial velocity

v is the common velocity

Given m1 = 2.7kg, u1 = 27m/s, m2 = 53kg, u2 = 0m/s (body at rest)

2.7(27)+53(0) = (2.7+53)v

72.9 = 55.7v

V = 72.9/55.7

Vf = 1.31m/s

c) kinetic energy = 1/2mv²

Kinetic energy of block 1 = 1/2×2.7(27)²

= 984.15Joules

Kinetic energy of block 2 before collision = 0kgm/s

Total KE before collision = 984.15Joules

Kinetic energy after collision = 1/2(2.7+53)1.31²

= 1/2×55.7×1.31²

= 47.79Joules

∆KE = 984.15-47.79

∆KE = 936.36Joules

7 0

3 years ago

he atomic radii of Li and O2- ions are 0.068 and 0.140 nm, respectively. (a) Calculate the force of attraction in newtons betwee

Crazy boy [7]

Answer:

a

$F = -1.07 *10^{-8} \ N$

b

$F_r = 1.07 *10^{-8} \ N$

Explanation:

Generally the force of attraction between this two irons is mathematically represented as

$F = \frac{k * [Q_{Li} ] * [Q_{O} ] }{ r^2}$

Here k is known as the proportionality constant with value $k = 2.31 * 10^ {-28} J \cdot m$

substituting -2 for $Q_{O}$ i.e the charge on oxygen , +1 for $Q_{Li}$ i.e the charge on Lithium and $[0.140 + 0.068 ] nm= 0.208 nm = 0.208*10^{-9}$ for r