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3 years ago

1. An object is moving to the right while a force directed to the left acts on the object. Is this force

Physics

1 answer:

Alex Ar [27]3 years ago

8 0

Answer:

Force is doing negative work here

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A car starts from rest and accelerates uniformly over a time of 7.25 seconds for a distance of 210 m. Determine the acceleration

lara31 [8.8K]

Answer:

Acceleration is 7.990487515m/s²

Initial velocity is 0m.s

Explanation:

s=ut+(1/2)at²

210=0(7.25)+(1/2)a(7.25²)

210=26.28125a

∴a=7.990487515m/s²

'Vi' or 'u' is the inital speed. Since it starts from rest, this equals 0.

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2 years ago

Which of these forces are acting within a nucleus? Check all that apply.

zavuch27 [327]

Answer:

Excuse me what?

Explanation:

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3 years ago

A block of 1 kg with a speed 1 m/s hits a spring placed horizontally as shown in the figure. If spring constant is 1000 N/m, fin

Evgen [1.6K]

Answer:

0.0316 m

Explanation:

Wok done = Energy change

Work done on the spring = Energy change of the block

Elastic Potential stored = Kinetic energy of the block

$\frac{1}{2} kx^{2} = \frac{1}{2} mv^{2}$

x = $\sqrt{v^{2}\frac{m}{k} }$

x = $\sqrt{1^{2}\frac{1}{1000} }$

x = 0.0316 m

k = spring constant

m = mass of block

v = velocity of the block

x = compression of spring

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3 years ago

A 10 g bullet is fired into, and embeds itself in, a 2 kg block attached to a spring with a force constant of 19.6 n/m and whose

dmitriy555 [2]

Answer:

$x=0.478\ m$ is the compression in the spring

Explanation:

Given:

mass of the bullet, $m=10\ g=0.01\ kg$

mass of block, $M=2\ kg$

stiffness constant of the spring, $k=19.6\ N.m^{-1}$

initial velocity of the spring just before it hits the block, $u=300\ m.s^{-1}$

<u>Now since the bullet-mass gets embed into the block, we apply the conservation of momentum as:</u>

$m.u=(M+m).v$

$0.01\times 300=(2+0.01)\times v$

$v=1.4925\ m.s^{-1}$

Now this kinetic energy of the combined mass gets converted into potential energy of the spring.

$\rm Kinetic\ energy=Spring\ potential\ energy$

$\frac{1}{2} (M+m).v^2=\frac{1}{2} k.x^2$

$\frac{1}{2} \times (2+0.01)\times 1.4925^2=\frac{1}{2} \times 19.6\times x^2$

$x=0.478\ m$ is the compression in the spring

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3 years ago

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Which physical phenomena is responsible for the earth’s sky appearing blue? scattering reflection dispersion refraction

klio [65]

Answer: Scattering reflection

Sunlight reaches earth's atmosphere and is scattered in all directions by all the gasses and particles in the air. Blue light is seen more than others because it travels as shorter, smaller waves. This is why we see a blue sky most of the time.

Explanation:

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3 years ago

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