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gayaneshka [121]
3 years ago
9

When there is no number in front of a chemical formula in a chemical equation, what number is understood?

Physics
1 answer:
Andre45 [30]3 years ago
5 0
<span>The number in front is the number of molecules (or atoms) taking part in the (balanced) chemical reaction equation.</span>
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EastWind [94]

Answer:

You may know that both velocity and acceleration have something to do with how fast an object moves. You’re right, but what’s the difference between these two terms in physics? Keep reading for more information about velocity, acceleration, and how to tell them apart.

Explanation:

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A plane progressive wave is represented by the equation y =2sin (2000πt- 0.5x) the symbols have their usual meanings. what is th
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The frequency of the wave is the frequency of that sine function ... 2,000π ... but that's the <u>angular </u>frequency, in radians per second.  

To convert angular frequency to Hz, we have to divide by 2π.

So the frequency of this wave is <em>1,000 Hz. </em>

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When very electronegative atoms, like oxygen, bond to atoms with lower electronegativity, like lithium, what's the result?
umka2103 [35]

(A) The oxygen atom becomes strongly negative.

Explanation:

When a very electronegative atom like oxygen bonds to an atom with a lower electronegativity, like lithium, the oxygen atom becomes strongly negative and the lithium becomes strongly positive.

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3 years ago
A rock hits a window and stops in 0.15 seconds. The net force on the rock is 58N during the collision. What is the magnitude of
nlexa [21]

Answer:

The change in momentum is  \Delta p =   0.7 \ kg\cdot m \cdot s^{-1}

Explanation:

From the question we are told that

    The time taken for the stone to stop is \Delta  t = 0.15 \ seconds

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The impulse of the rock can be mathematically represented as

     I  =  F * \Delta t

Substituting values

     I  =  58 * 0.15

    I  =  0.7\  kg * m  * s^{-1}

Now impulse is defined as  the rate at which momentum change

   Hence the change in momentum \Delta p  of the rock is equal to the impulse of the rock

 So  

       \Delta p =  I  =  0.7 \ kg\cdot m \cdot s^{-1}

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