Answer:
The bearing of Q from P is 155°.
Step-by-step explanation:
In the attached photo,
Fig 1. gives details about the question and fig 2. gives the answer to the question.
From fig 1:
b° + 335° = 360° (sum of angle at a point)
b° + 335° = 360°
Collect like terms
b° = 360° – 335°
b° = 25°
a° + b° = 180° (sum of angle in a straight line)
a° + b° = 180°
b° = 25°
a° + 25° = 180°
Collect like terms
a° = 180° – 25°
a° = 155°
a° gives the bearing of Q from P.
Therefore, the bearing of Q from P is 155°.
Fig 2 on the attached photo shows the the bearing of Q from P.
Answer:
-4x² - 2xy + 5y²
Step-by-step explanation:
Step 1: Write expression
(3x² - 5xy + 2y²) - (7x² - 3xy - 3y²)
Step 2: Distribute negative
3x² - 5xy + 2y² - 7x² + 3xy + 3y²
Step 3: Combine like terms
-4x² - 2xy + 5y²
Answer:
The new width = 2 inches
Step-by-step explanation:
Original dimensions of the rectangular photo:
Length : width = 8 inches : 4 inches
Reduced dimensions of the rectangular photo:
Let
x = the new width
Length : width = 4 inches : x inches
Equate both dimensions to get the value of x
Length : width
8 inches : 4 inches = 4 inches : x inches
8 / 4 = 4 / x
Cross product
8 * x = 4 * 4
8x = 16
x = 16/8
x = 2 inches
The new width = 2 inches
A 10x7 =70 and u use i-ready cool
