Chart and assignment above, any actual help is appreciated!! Eighth grade math :)
1 answer:
1. Car Mart sell 11 cars per day.
You can use the table by looking at day 2 and day 3. You can see underneath it, it shows how many cars is left after that particular day. So from day 2, you have 43 cars left and day 3, you got 32 cars left. From 43 car to 32 car is losing 11 car. So each day the Car Mart sell 11 car.
2. First we know that after 3 days, Winston have 32 cars left and after 5 day, it has 12 cars left.
Here’s the chart that I made for Winston:
Each day, Winston’s sell 10 cars. (Lose 10 cars per day)
You can use the table by looking at day 2 and day 3. You can see underneath it, it shows how many cars is left after that particular day. So from day 2, you have 43 cars left and day 3, you got 32 cars left. From 43 car to 32 car is losing 11 car. So each day the Car Mart sell 11 car.
2. First we know that after 3 days, Winston have 32 cars left and after 5 day, it has 12 cars left.
Here’s the chart that I made for Winston:
Each day, Winston’s sell 10 cars. (Lose 10 cars per day)
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Answer:
69.01 m
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you ...
Tan = Opposite/Adjacent
The tangent function is useful for problems like this. Let the height of the spire be represented by h. The distance (d) across the plaza from the first surveyor satisfies the relation ...
tan(50°) = (h -1.65)/d
Rearranging to solve for d, we have ...
d = (h -1.65)/tan(50°)
The distance across the plaza from the second surveyor satisfies the relation ...
tan(30°) = (101.65 -h)/d
Rearranging this, we have ...
d = (101.65 -h)/tan(30°)
Equating these expressions for d, we can solve for h.
(h -1.65)/tan(50°) = (101.65 -h)/tan(30°)
h(1/tan(50°) +1/tan(30°)) = 101.65/tan(30°) +1.65/tan(50°)
We can divide by the coefficient of h and simplify to get ...
h = (101.65·tan(50°) +1.65·tan(30°))/(tan(30°) +tan(50°))
h ≈ 69.0148 ≈ 69.01 . . . . meters
The tip of the spire is 69.01 m above the plaza.
