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3 years ago

9

joe deposits $1500 in an account that pays 3% annual interest compounded conitiniously how much will joe have in his account aft

er 5 years

1 answer:

konstantin123 [22]3 years ago

3 0

Answer:A = 1500e^(0.03 * 5) = 1500e^(0.15)

use definition of logarithm

0.15 = ln(A / 1500)

0.15 = ln(A) - ln(1500)

ln(A) = 0.15 + ln(1500) = 0.15 + 7.313220387 = 7.463220387

Step-by-step explanation:

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