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2 years ago

9

joe deposits $1500 in an account that pays 3% annual interest compounded conitiniously how much will joe have in his account aft

er 5 years

1 answer:

konstantin123 [22]2 years ago

3 0

Answer:A = 1500e^(0.03 * 5) = 1500e^(0.15)

use definition of logarithm

0.15 = ln(A / 1500)

0.15 = ln(A) - ln(1500)

ln(A) = 0.15 + ln(1500) = 0.15 + 7.313220387 = 7.463220387

Step-by-step explanation:

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Write each as a decimal. Round to the thousandths place.<br> 9) 78.4%<br> 10) 29%<br> Help

fomenos

Answer:

$(a) 78.4\% = 0.784$

$(b) 29\% =0.290$

Step-by-step explanation:

Required

As a decimal to nearest thousandth

Solving (a): 78.4%

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Express as fraction

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Solving (b): 29%

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Express as fraction

$29\% =\frac{29}{100}$

Solve fraction

$29\% =0.29$

Approximate

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