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snow_lady [41]
3 years ago
13

-2 (3 + 5y -10) = 34

Mathematics
2 answers:
IrinaK [193]3 years ago
7 0
-2 (3+5y-10) = 34
Step 1) -6-10y+20=34
Step 2) -10y+20=40
Step 3) -10y=20
Step 4) y = -2
Answer is -2
brilliants [131]3 years ago
7 0
What I did to solve this
1. First add 10 to -10
2. Add 10 to 34
3. Minus 3 to the 3 and now 44(was 34)
4. Plus 2 to the -2 and to 41
5. 5y divided by 5 and 43 divided by 5
6. Y=8.6
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Find the measure of the the sides of DEF then classify it by it sides. <br> D(8,-6) E(-1,-3) F(-2,5)
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Answer:

Part a) The measure of the sides of triangle DEF are

d_D_E=\sqrt{90}\ units

d_E_F=\sqrt{65}\ units

d_D_F=\sqrt{221}\ units

Part b) Is a scalene triangle

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have the coordinates

D(8,-6) E(-1,-3) F(-2,5)

step 1

Find the length side DE

D(8,-6) E(-1,-3)

substitute in the formula

d=\sqrt{(-3+6)^{2}+(-1-8)^{2}}

d=\sqrt{(3)^{2}+(9)^{2}}

d_D_E=\sqrt{90}\ units

step 2

Find the length side EF

E(-1,-3) F(-2,5)

substitute in the formula

d=\sqrt{(5+3)^{2}+(-2+1)^{2}}

d=\sqrt{(8)^{2}+(-1)^{2}}

d_E_F=\sqrt{65}\ units

step 3

Find the length side DF

D(8,-6) F(-2,5)

substitute in the formula

d=\sqrt{(5+6)^{2}+(-2-8)^{2}}

d=\sqrt{(11)^{2}+(-10)^{2}}

d_D_F=\sqrt{221}\ units

step 4

Classify the triangle by the measure of its sides

we have

d_D_E=\sqrt{90}\ units

d_E_F=\sqrt{65}\ units

d_D_F=\sqrt{221}\ units

so

Is a scalene triangle, because is a triangle in which all three sides have different lengths.

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