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2 years ago

Go follow my meme page on Insta gram please I just started it

SAT

1 answer:

julia-pushkina [17]2 years ago

8 0

Answer:

you sound like that guy on tik who yells and makes these angry faces because were sad and he makes our day better i forgot his user

Explanation:

you are very inspirational i hope ill bust some tears at your memes tho

You might be interested in

One mole of potassium permanganate kmno4 contains grams of oxygen.

Pepsi [2]

1 mol KMnO₄ contains 4 mol O, which has a molar mass of about 15.999 g/mol. Then the mass of O in the sample is

(4 mol) (15.999 g/mol) ≈ 63.996 g

8 0

1 year ago

Discuss five secrets that turn life changes into life successes

Feliz [49]

Answer:

#Secret 1 – Be Passionate About Goals.

#secret 2 – Set Your Mind On Positive Mode.

#Secret 3 – Create Your Own Strategies.

#Secret 4 – Value Your Time.

#Secret 5 – Make Your Mission Enthusiastic.

Explanation:

hope these help

8 0

2 years ago

Examine the information in the url below. Http://www.Example/home/index.Html in the url, what is the subdomain and what is the d

alexdok [17]

Domain is Example and subdomain is www.

3 0

2 years ago

choose a synonym for the word in parentheses below. the ice could slide down the slope if there is too much (pressure) on the gl

antiseptic1488 [7]

the answer is B. Strain

8 0

2 years ago

Students in a statistics class are conducting a survey to estimate the mean number of units students at their college are enroll

Andrew [12]

Using the t-distribution, as we have the standard deviation for the sample, it is found that the 95% confidence interval for the number of units students in their college are enrolled in is (11.7, 12.7).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm t\frac{s}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

t is the critical value.

n is the sample size.

s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed <em>95% confidence interval</em>, with 49 - 1 = <em>48 df</em>, is t = 2.0106.

Hence:

$\overline{x} - t\frac{s}{\sqrt{n}} = 12.2 - 2.0106\frac{1.6}{\sqrt{49}} = 11.7$

$\overline{x} + t\frac{s}{\sqrt{n}} = 12.2 + 2.0106\frac{1.6}{\sqrt{49}} = 12.7$

The 95% confidence interval for the number of units students in their college are enrolled in is (11.7, 12.7).

More can be learned about the t-distribution at brainly.com/question/16162795

4 0

1 year ago