1/3+g this is the equation
Answer:
8+n divded by 6=27
Step-by-step explanation:
Step-by-step explanation:
Answer:
<em>DF = 10 units</em>
![m\angle DFG = 28^\circ](https://tex.z-dn.net/?f=m%5Cangle%20DFG%20%3D%2028%5E%5Ccirc)
<em>EG = 5.04</em>
Step-by-step explanation:
<u>Properties of Rhombus
es</u>
- All Sides Of The Rhombus Are Equal.
- The Opposite Sides Of A Rhombus Are Parallel.
- Opposite Angles Of A Rhombus Are Equal.
- In A Rhombus, Diagonals Bisect Each Other At Right Angles.
- Diagonals Bisect The Angles Of A Rhombus.
The image contains a rhombus with the following data (assume the center as point O):
DO = 5 units
GF = 5.6 units
![m\angle FEO = 62^\circ](https://tex.z-dn.net/?f=m%5Cangle%20FEO%20%3D%2062%5E%5Ccirc)
4. Calculate DF
Applying property 4, diagonals bisect each other, thus the length of DF is double the length of DO, i.e. DF=2*5 = 10:
DF = 10 units
5. Calculate ![m\angle DFG](https://tex.z-dn.net/?f=m%5Cangle%20DFG)
Applying property 4 in triangle EFO, the center angle is 90°, thus angle EFO has a measure of 90°-62°=28°.
Applying property 5, this angle is half of the measure of angle EFG and angle DFG has the same measure of 28°.
![m\angle DFG = 28^\circ](https://tex.z-dn.net/?f=m%5Cangle%20DFG%20%3D%2028%5E%5Ccirc)
6. FG is the hypotenuse of triangle OFG, thus:
![OG^2=FG^2-OF^2](https://tex.z-dn.net/?f=OG%5E2%3DFG%5E2-OF%5E2)
![OG^2=5.6^2-5^2](https://tex.z-dn.net/?f=OG%5E2%3D5.6%5E2-5%5E2)
![OG^2=6.36](https://tex.z-dn.net/?f=OG%5E2%3D6.36)
![OG=\sqrt{6.36}=2.52](https://tex.z-dn.net/?f=OG%3D%5Csqrt%7B6.36%7D%3D2.52)
EG is double OG: OG=2*2.52=5.04
EG = 5.04
Julia has determined that CE is perpendicular bisector of AB. The next step of a valid proof would be: <em>B. AC = BC based on the </em><em>perpendicular bisector theorem</em>.
<h3>What is the Perpendicular Bisector Theorem?</h3>
The perpendicular bisector theorem states that if a point is located on a segment (perpendicular bisector) that divides another segment into two halves, then it is equidistant from the two endpoints of the segment that is divided.
Thus, since Julia has determined that CE is perpendicular bisector of AB, therefore the next step of a valid proof would be: <em>B. AC = BC based on the </em><em>perpendicular bisector theorem</em>.
Learn more about the perpendicular bisector theorem on:
brainly.com/question/2035717