Question

What is the distance in meter of an object that has an angular diameter of 30 arcseconds and a linear diameter of 10 cm?

Answer 1

Answer:

The distance is 688.2 m.

Step-by-step explanation:

Linear diameter, d= 10 cm

Angle = 30 arc seconds = 0.00833 degrees = $=0.00833\times \frac{\pi}{180} rad$

Let the distance is D.

$D=\frac{d}{Angle}\\\\D = \frac{0.1}{0.00833\times 3.14}\times 180\\\\D= 688.2 m$

 

Answer 2

Answer:

Distance of object = 0.0144 meter

Step-by-step explanation:

Given:

Angular diameter = 30 arcseconds = 30[100 / 3600]

Length of diameter = 10 cm

Find:

Distance of object

Computation:

Distance of object = [(2)(a)][TanФ / 2]

Distance of object = [(2)(10)][Tan(300 / 7200]

Distance of object = [20][Tan 0.04167]

Distance of object = [20][0.00072]]

Distance of object = 0.0144 meter