help please! indicate the equation of the given line in standard form the line that contains the point q 1,2 and is parallel to
the line whose equation is y-4=2/3(x-3)
1 answer:
9514 1404 393
Answer:
2x -3y = 8
Step-by-step explanation:
It is helpful to start by putting the given equation in standard form
y -4 = 2/3(x -3)
3y -12 = 2x -6 . . . . . . multiply by 3, eliminate parentheses
2x -3y = -6 . . . . . . . . add 6-3y to get standard form
When point Q is substituted for x and y, the new constant on the right is ...
2x -3y = 2(1) -3(-2)
2x -3y = 8
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<em>Additional comment</em>
The equation is in standard form when the leading coefficient is positive, all coefficients are mutually prime integers, and the form is ...
ax +by = c
Note that we subtracted the y-term, rather than the x-term from the given equation. This is so the x-term would have a positive coefficient. We could have written our standard form equation as ...
3y -2x = -8
but it is a bit unusual to have the variables not be in alphabetical order.
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