Question

help please! indicate the equation of the given line in standard form the line that contains the point q 1,2 and is parallel to the line whose equation is y-4=2/3(x-3)​

Answer 1

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Answer:

  2x -3y = 8

Step-by-step explanation:

It is helpful to start by putting the given equation in standard form

  y -4 = 2/3(x -3)

  3y -12 = 2x -6 . . . . . . multiply by 3, eliminate parentheses

  2x -3y = -6 . . . . . . . .  add 6-3y to get standard form

When point Q is substituted for x and y, the new constant on the right is ...

  2x -3y = 2(1) -3(-2)

  2x -3y = 8

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Additional comment

The equation is in standard form when the leading coefficient is positive, all coefficients are mutually prime integers, and the form is ...

  ax +by = c

Note that we subtracted the y-term, rather than the x-term from the given equation. This is so the x-term would have a positive coefficient. We could have written our standard form equation as ...

  3y -2x = -8

but it is a bit unusual to have the variables not be in alphabetical order.