Answer:
LLgg, Llgg , two out of 16
Explanation:
Given,
Dominant - Long wings and Gray color
Recessive - Short wings and Brown color
Let the allele for long wings be "L" and the allele for short wings be "l".
Let the allele for brown color be "g" and allele for gray color be "G"
Genotype of parents
LlGg
Gametes of the parent
LG, Lg, lG, lg
Dihybrid cross is between LlGg and LlGg
The offspring produces will be as follows -
LG Lg lG lg
LG LLGG LLGg LlGG LlGg
Lg LLGg LLgg LlGg Llgg
lG LlGG LlGg llGG llGg
lg LlGg Llgg llGg llgg
Offspring with long wings and brown color – LLgg, Llgg , two out of 16
Electricity is caused by moving particles that have either a negative or postivite charge
ATP stores and transports energy in the cells, usually in the mitochondria. Energy is released by hydrolysis (carbohydrates being broken down into sugar molecules), which eventually results in forming ADP (adenosine diphosphate) that absorbs the energy and recharges the phosphate group and ATP
I think D is the right answer.
Admitting that the "a" is a capital A for normal pigmentation and "d" is a capital D for dimpled chin, meaning that these are the dominant traits, the fraction expected to be albino with a non-dimpled chin is of 1/16.
When two heterozygous are crossed and two characteristics are being analysed, the offspring quantity that will possess the two recessive traits can be represented by 1/16. This is easily confirmed when a Punnett square is made. Considering that both parents were heterozygous, on both sides of the crossing in the Punnett square, you would have the following alleles' combination: AD, Ad, aD, and ad. The offspring that would be homozygous recessive (aadd) would correspond to only 1/16.
